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If d is the average (arithmetic mean) of a, b and c, then c =

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Joined: 02 Sep 2009
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If d is the average (arithmetic mean) of a, b and c, then c =  [#permalink]

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21 Jan 2018, 02:22
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Difficulty:

5% (low)

Question Stats:

98% (00:34) correct 2% (00:00) wrong based on 51 sessions

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If d is the average (arithmetic mean) of a, b and c, then c =

(A) 3d - a - b
(B) 3d - a + b
(C) d - 3a -3b
(D) d - 3a + 3b
(E) (a + b)/(3d)

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If d is the average (arithmetic mean) of a, b and c, then c =  [#permalink]

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21 Jan 2018, 02:29
Bunuel wrote:
If d is the average (arithmetic mean) of a, b and c, then c =

(A) 3d - a - b
(B) 3d - a + b
(C) d - 3a -3b
(D) d - 3a + 3b
(E) (a + b)/(3d)

given $$a+b+c=3d$$

$$=>c=3d-a-b$$

Option A
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Re: If d is the average (arithmetic mean) of a, b and c, then c =  [#permalink]

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21 Jan 2018, 08:03
Bunuel wrote:
If d is the average (arithmetic mean) of a, b and c, then c =

(A) 3d - a - b
(B) 3d - a + b
(C) d - 3a -3b
(D) d - 3a + 3b
(E) (a + b)/(3d)

a + b + c = 3d

So, c = 3d - a - b , answer will be (A)
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Abhishek....

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Re: If d is the average (arithmetic mean) of a, b and c, then c = &nbs [#permalink] 21 Jan 2018, 08:03
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