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Sub 505 (Easy)|   Sequences|      
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Bunuel
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If each number in a sequence is three more than the previous number, a 01 Jan 2018, 11:56
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88% (01:26) correct 12% (01:52) wrong based on 279 sessions

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If each number in a sequence is three more than the previous number, and the sixth number is 32, what is the 100th number?

A. 312
B. 313
C. 314
D. 315
E. 316
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C
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sohinide
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If each number in a sequence is three more than the previous number, a 01 Jan 2018, 11:57
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Bunuel
If each number in a sequence is three more than the previous number, and the sixth number is 32, what is the 100th number?
Show more

If each number in a sequence is three more than the previous number, and the
sixth number is 32, what is the 100th number?

The answer says -
From the sixth to the one hundredth term, there are 94 “jumps” of 3. Since 94 x 3 = 282, there is an
increase of 282 from the sixth term to the one hundredth term:
32 + 282 = 314.

Can someone please help me understand how the 94 figure is arrived at?
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s8kadian
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If each number in a sequence is three more than the previous number, a 01 Jan 2018, 12:26
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sohinide
Bunuel
If each number in a sequence is three more than the previous number, and the sixth number is 32, what is the 100th number?

If each number in a sequence is three more than the previous number, and the
sixth number is 32, what is the 100th number?

The answer says -
From the sixth to the one hundredth term, there are 94 “jumps” of 3. Since 94 x 3 = 282, there is an
increase of 282 from the sixth term to the one hundredth term:
32 + 282 = 314.

Can someone please help me understand how the 94 figure is arrived at?
Show more


6th no -- 32 ....7th - 35 .....100th --?

sp 100 - 6 = 94 terms between 6 n 100

each term is three more than the previous number

so all 94 Ts X 3 = 282

94 terms + 6 terms = 100th term
282 + 32 = 314
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gracie
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If each number in a sequence is three more than the previous number, a 01 Jan 2018, 21:20
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Bunuel
If each number in a sequence is three more than the previous number, and the sixth number is 32, what is the 100th number?
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32-5*3=first number=17
17+99*3=100th number=314
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luffy_ueki
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If each number in a sequence is three more than the previous number, a 01 Jan 2018, 21:25
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Since there is a constant difference of 3 between terms in the series => Arithmetic progression
d=3 ;
sinc 6th term =32
tn = a+(n-1)d
t6 = a+(5)*3
a=17

For 100th term
t100 = a+99*d
=17+99*3
=17+297
=314 (100th term)
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If each number in a sequence is three more than the previous number, a 21 Mar 2018, 01:04
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d = 3

a1 + 5d = 32

=) a1 = 17

and, a100 = a1 + 99d

=) a100 = 314

thanks
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Docmba68
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If each number in a sequence is three more than the previous number, a 27 May 2026, 09:23
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Bunuel
If each number in a sequence is three more than the previous number, and the sixth number is 32, what is the 100th number?

A. 312
B. 313
C. 314
D. 315
E. 316
Show more

Suppose 1st no is x f/b x+3, x+6, x+9, x+12, x+15
Now x+15 = 6th term =32
ie x =17

Now see a pattern here
X+3 is 2nd term nd x+15 is 6th term nd its 3’s table
ie 3*5=15 leads to 6th term ie one more than what 3 being multipied to

This implies 100th term will be x+ 3*99
ie x+ 297= answer
Ie 17+ 297 =314
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Bunuel
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