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if each of the following fractions were written as a repeating decimal, which would have been the longest sequence of different digits
1 2/11
2 1/3
3 41/99
4 2/3
5 23/37
Guys pls explain the shortest way to solve such problems
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the way I would handle it is. remove the ones which you can calculate in your brain easily . this would remove 1/3, 2/3..
then if the two digits in the denominator are the same then take it as a rule that its gonna be a repeating decimal remove those too. which in this case will be 2/11, 41/99. that would leave us with the most odd one which is 23/37 which is a transcendental number.
answer is E
the way I would handle it is. remove the ones which you can calculate in your brain easily . this would remove 1/3, 2/3..
then if the two digits in the denominator are the same then take it as a rule that its gonna be a repeating decimal remove those too. which in this case will be 2/11, 41/99. that would leave us with the most odd one which is 23/37 which is a transcendental number. answer is E
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this is a fair generalization, but it is not a rule. I just tried a bunch of them on the calculator and it does not always work out exactly. 9/88, for example, is .10227272727, and 4/55 is .0727272
23/37 is .621621621.
no fraction can be a transcendental number, incidentally, because a transcendental number is by definition irrational, and no fraction is irrational. A rational number is defined as any number that can be written as a/b.
I wouldn't take chances with this problem. I'd wipe out 1/3 and 2/3 for obvious reasons and then just do the division on the other three. How long does that really take to ensure a correct answer?
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