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stonecold
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25 Aug 2016, 13:49
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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If each term in the sum a1+a2+a3+...+an either 2 or 22 and the sum equals 100, which of the following could be equal to n?
A. 38
B. 39
C. 40
D. 41
E. 42
Give me an Algebraic Solution..!!! No Hit and trials
Note => This question is just for practise . After doing the above try this Official GMAT prep Question too -> if-each-term-in-the-sum-a1-a2-a3-an-is-either-7-or-93974.html
A. 38
B. 39
C. 40
D. 41
E. 42
Give me an Algebraic Solution..!!! No Hit and trials
Note => This question is just for practise . After doing the above try this Official GMAT prep Question too -> if-each-term-in-the-sum-a1-a2-a3-an-is-either-7-or-93974.html
27 Aug 2016, 01:45
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stonecold
If each term in the sum a1+a2+a3+...+an either 2 or 22 and the sum equals 100, which of the following could be equal to n?
A. 38
B. 39
C. 40
D. 41
E. 42
Give me an Algebraic Solution..!!! No Hit and trials
Note => This question is just for practise . After doing the above try this Official GMAT prep Question too -> if-each-term-in-the-sum-a1-a2-a3-an-is-either-7-or-93974.html
A. 38
B. 39
C. 40
D. 41
E. 42
Give me an Algebraic Solution..!!! No Hit and trials
Note => This question is just for practise . After doing the above try this Official GMAT prep Question too -> if-each-term-in-the-sum-a1-a2-a3-an-is-either-7-or-93974.html
We are given 22k + 2k' = 100 .
Also, k+k' = n
In order to find the maximum value of n, we need to maximize the value of k' and minimize the value of k. Also, need to maintain the value of n an integer.
We cannot take k = 0, as we have atleast one 22 in the numbers.
So, lets say k=1, we will have 2k'=78 or k'=39
Therefore, n = 1+39=40
Hence, C
General Discussion
25 Aug 2016, 14:13
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Min value of 'n' can be 10 i.e 4*22+6*12 => 22+22+22+22+2+2+2+2+2+2 = 100
Since we don't have 10 in the options proceed further, (10-1)+22/2 => 20 digits, which is again not in the options
(20-1) + 22/2 = 30 digits ( not in options)
(30-1) + 22/2 = 40 digits
Hence C.
Since we don't have 10 in the options proceed further, (10-1)+22/2 => 20 digits, which is again not in the options
(20-1) + 22/2 = 30 digits ( not in options)
(30-1) + 22/2 = 40 digits
Hence C.
