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15 Jan 2021, 10:45
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
77% (01:19) correct
23%
(01:15)
wrong
based on 141
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If exactly one real value of x satisfies the equation x^2 + ax + 16 = 0, which of the following is a possible value of a ?
(A) –8
(B) –4
(C) 4
(D) 6
(E) 10
(A) –8
(B) –4
(C) 4
(D) 6
(E) 10
15 Jan 2021, 10:52
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For a quadratic equation to have exactly one solution, the determinant must be equal to 0.
Hence,
\(a^2-4(1)(16) = 0\)
\(a^2 = 64\)
or, a = +8 or -8
Hence, Ans is A IMO
Hence,
\(a^2-4(1)(16) = 0\)
\(a^2 = 64\)
or, a = +8 or -8
Hence, Ans is A IMO
15 Jan 2021, 11:02
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Asked: If exactly one real value of x satisfies the equation x^2 + ax + 16 = 0, which of the following is a possible value of a ?
For exactly 1 real root
b^2-4ac=0
a^2 -64 =0
a={8,-8}
IMO A
Posted from my mobile device
For exactly 1 real root
b^2-4ac=0
a^2 -64 =0
a={8,-8}
IMO A
Posted from my mobile device
