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If f(x) = x^3 − 5 and f(k) = 3 then k =

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Math Expert
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Joined: 02 Sep 2009
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If f(x) = x^3 − 5 and f(k) = 3 then k =  [#permalink]

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New post 21 Aug 2018, 06:28
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

93% (00:42) correct 8% (00:38) wrong based on 54 sessions

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If f(x) = x^3 − 5 and f(k) = 3 then k =  [#permalink]

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New post 21 Aug 2018, 06:30
Bunuel wrote:
If f(x) = x^3 − 5 and f(k) = 3 then k =

A. -22
B. 2
C. 4
D. 6
E. 22


\(f(x)=x^3-5\)

\(f(k)=k^3-5=3\)

\(=>k^3=8 => k=2\)

Option B
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Re: If f(x) = x^3 − 5 and f(k) = 3 then k =  [#permalink]

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New post 21 Aug 2018, 14:07
Bunuel wrote:
If f(x) = x^3 − 5 and f(k) = 3 then k =

A. -22
B. 2
C. 4
D. 6
E. 22



f(x) = x^3 − 5

and

f(k) = 3


So, \(x^3 - 5 = 3\)

\(x^3 = 8\)

\(x^3 = 2^3\)

The best answer is B.
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Re: If f(x) = x^3 − 5 and f(k) = 3 then k =  [#permalink]

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New post 23 Aug 2018, 16:58
Bunuel wrote:
If f(x) = x^3 − 5 and f(k) = 3 then k =

A. -22
B. 2
C. 4
D. 6
E. 22


Since f(k) = 3, we substitute k for x in the function x^3 − 5, obtaining :

k^3 - 5 = 3

k^3 = 8

k = 2

Answer: B
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Re: If f(x) = x^3 − 5 and f(k) = 3 then k =   [#permalink] 23 Aug 2018, 16:58
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