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If, for all positive integer values of n, P(n) is defined as [#permalink]

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25 Apr 2013, 21:43

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If, for all positive integer values of n, P(n) is defined as the sum of the smallest n prime numbers, then which of the following quantities are odd integers?

I. P(10) II. P(P(10)) III. P(P(P(10)))

(A) I only (B) I and II only (C) I and III only (D) II and III only (E) I, II, and III

Re: If, for all positive integer values of n, P(n) is defined as [#permalink]

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25 Apr 2013, 22:41

emmak wrote:

If, for all positive integer values of n, P(n) is defined as the sum of the smallest n prime numbers, then which of the following quantities are odd integers? I. P(10) II. P(P(10)) III. P(P(P(10)))

(A) I only (B) I and II only (C) I and III only (D) II and III only (E) I, II, and III

Express appreciation by pressing KUDOS button

2 is the only even prime number. Now, the sum of first 10 prime numbers = 9*odd + 2 = odd. Thus P(10) = odd.

Again, the sum of the first n -odd primes = (n-1)*odd+2 = even.Thus, p(P(10)) = even.

Similarly, the sum of the first m - even primes = (m-1)*odd+2 = odd.

If, for all positive integer values of n, P(n) is defined as the sum of the smallest n prime numbers, then which of the following quantities are odd integers? I. P(10) II. P(P(10)) III. P(P(P(10)))

(A) I only (B) I and II only (C) I and III only (D) II and III only (E) I, II, and III

Express appreciation by pressing KUDOS button

This kind of question can give students fits. The key is to figure out what is being asked. The function P is summing up the first N prime numbers, so for example P(3) = 2 + 3 + 5. The total is 10. If I picked P(4), I'd get the same sum + 7, or 17.

Since the question hinges on whether the sum is even or odd, the only number that's unique in this circumstance is 2, as it is the only even prime number in an otherwise homogenous sea of odd numbers. Thus P(1) is even, P(2) is odd, P(3) is even again and P(4) is odd again. This is the pattern, so clearly P(10) will be 2 + nine odd numbers, so it will be odd. We can eliminate D.

P(P(10)) is where this starts getting interesting. You're doing the same test on a number we don't exactly know, but we know it must be odd. Since we know the pattern, the odd number will give us even. P(P(10)) will not be odd, eliminate B and E.

P(P(10))) will be the same function over a number we just calculated would be even. Hence it must be odd again. Eliminate A, the answer must be C.

Function questions are among the least understood questions on the GMAT, and this type of question can get people spending 3-4 minutes extrapolating numbers. If you understand the pattern using a small sample and reasoning, you can get this question right in under two minutes.

Re: If, for all positive integer values of n, P(n) is defined as [#permalink]

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26 Apr 2013, 09:48

VeritasPrepRon wrote:

emmak wrote:

If, for all positive integer values of n, P(n) is defined as the sum of the smallest n prime numbers, then which of the following quantities are odd integers? I. P(10) II. P(P(10)) III. P(P(P(10)))

(A) I only (B) I and II only (C) I and III only (D) II and III only (E) I, II, and III

Express appreciation by pressing KUDOS button

This kind of question can give students fits. The key is to figure out what is being asked. The function P is summing up the first N prime numbers, so for example P(3) = 2 + 3 + 5. The total is 10. If I picked P(4), I'd get the same sum + 7, or 17.

Since the question hinges on whether the sum is even or odd, the only number that's unique in this circumstance is 2, as it is the only even prime number in an otherwise homogenous sea of odd numbers. Thus P(1) is even, P(2) is odd, P(3) is even again and P(4) is odd again. This is the pattern, so clearly P(10) will be 2 + nine odd numbers, so it will be odd. We can eliminate D.

P(P(10)) is where this starts getting interesting. You're doing the same test on a number we don't exactly know, but we know it must be odd. Since we know the pattern, the odd number will give us even. P(P(10)) will not be odd, eliminate B and E.

P(P(10))) will be the same function over a number we just calculated would be even. Hence it must be odd again. Eliminate A, the answer must be C.

Function questions are among the least understood questions on the GMAT, and this type of question can get people spending 3-4 minutes extrapolating numbers. If you understand the pattern using a small sample and reasoning, you can get this question right in under two minutes.

Hope this helps! -Ron

Ah that makes sense... took me a while.

I. Even + 9 odds = odd. II. Even + (odd * (odd - 1)) = even III. Even + (odd * (even - 1)) = odd

Re: If, for all positive integer values of n, P(n) is defined as [#permalink]

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26 Feb 2014, 06:35

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Nice question +1. For this I would identify two cases: First we know that the only even number is 2. Therefore, if the number of prime integers that is n is even then the sum is odd, while if n is odd the sum is even.

In I we have that n is even therefore sum is odd. TRUE.

In II we have that the sum is odd so if we take that n is odd then the sum again will be even. FALSE.

In III, we get that the sum of n=10 is odd. Now the sum of odd is even and again the sum of even is odd. So III is TRUE as well.

Re: If, for all positive integer values of n, P(n) is defined as [#permalink]

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26 Apr 2015, 22:03

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Re: If, for all positive integer values of n, P(n) is defined as [#permalink]

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28 Apr 2016, 20:21

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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: If, for all positive integer values of n, P(n) is defined as [#permalink]

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06 Aug 2017, 08:30

VeritasPrepRon wrote:

emmak wrote:

If, for all positive integer values of n, P(n) is defined as the sum of the smallest n prime numbers, then which of the following quantities are odd integers? I. P(10) II. P(P(10)) III. P(P(P(10)))

(A) I only (B) I and II only (C) I and III only (D) II and III only (E) I, II, and III

Express appreciation by pressing KUDOS button

This kind of question can give students fits. The key is to figure out what is being asked. The function P is summing up the first N prime numbers, so for example P(3) = 2 + 3 + 5. The total is 10. If I picked P(4), I'd get the same sum + 7, or 17.

Since the question hinges on whether the sum is even or odd, the only number that's unique in this circumstance is 2, as it is the only even prime number in an otherwise homogenous sea of odd numbers. Thus P(1) is even, P(2) is odd, P(3) is even again and P(4) is odd again. This is the pattern, so clearly P(10) will be 2 + nine odd numbers, so it will be odd. We can eliminate D.

P(P(10)) is where this starts getting interesting. You're doing the same test on a number we don't exactly know, but we know it must be odd. Since we know the pattern, the odd number will give us even. P(P(10)) will not be odd, eliminate B and E.

P(P(10))) will be the same function over a number we just calculated would be even. Hence it must be odd again. Eliminate A, the answer must be C.

Function questions are among the least understood questions on the GMAT, and this type of question can get people spending 3-4 minutes extrapolating numbers. If you understand the pattern using a small sample and reasoning, you can get this question right in under two minutes.

Hope this helps! -Ron

Thanks for the solution.... Putting numbers to solve this kind of question can take 5 minutes easily.... We must follow the right approach to solve the question quickly...
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Re: If, for all positive integer values of n, P(n) is defined as [#permalink]

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07 Aug 2017, 22:15

emmak wrote:

If, for all positive integer values of n, P(n) is defined as the sum of the smallest n prime numbers, then which of the following quantities are odd integers?

I. P(10) II. P(P(10)) III. P(P(P(10)))

(A) I only (B) I and II only (C) I and III only (D) II and III only (E) I, II, and III

P(n) = Sum of 1st n prime numbers. Among these prime numbers only 2 i.e. first prime number is even. P(10 )= Sum of 2 and 9 odd numbers = even +9*odd = odd P(P(10)) = P(odd) = even + even *odd = even P(P(P(10))) = P(even) = even + odd * odd = odd.

So I and III only Hence Answer C _________________