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# If g(x)=ax^5+bx^3+1, and g(5)=10, then g(-5)=? (A) -10 (B)

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Current Student
Joined: 11 May 2008
Posts: 552
If g(x)=ax^5+bx^3+1, and g(5)=10, then g(-5)=? (A) -10 (B) [#permalink]

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31 Jul 2008, 10:56
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

. If g(x)=ax^5+bx^3+1, and g(5)=10, then g(-5)=?
(A) -10
(B) -8
(C) -6
(D) 0
(E) 4
Director
Joined: 12 Jul 2008
Posts: 513
Schools: Wharton
Re: DIFF type PROB... [#permalink]

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31 Jul 2008, 10:59
arjtryarjtry wrote:
. If g(x)=ax^5+bx^3+1, and g(5)=10, then g(-5)=?
(A) -10
(B) -8
(C) -6
(D) 0
(E) 4

B

10 = a*5^5 + b*5^3 +1
a*5^5 + b*5^3 = 9

g(-5) = a(-5)^5 + b(-5)^3 + 1
= -a*5^5 - b*5^3 + 1
= -(a*5^5 + b*5^3) + 1
= -9 + 1
= -8
Current Student
Joined: 11 May 2008
Posts: 552
Re: DIFF type PROB... [#permalink]

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31 Jul 2008, 11:00
...ZOINKK..NICE
VP
Joined: 17 Jun 2008
Posts: 1325
Re: DIFF type PROB... [#permalink]

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31 Jul 2008, 11:05
arjtryarjtry wrote:
. If g(x)=ax^5+bx^3+1, and g(5)=10, then g(-5)=?
(A) -10
(B) -8
(C) -6
(D) 0
(E) 4

clearly -8 is answer :
g(x)+g(-x)= 2
=> g(-5)= 2- g(5)=2-10=-8
_________________

cheers
Its Now Or Never

Re: DIFF type PROB...   [#permalink] 31 Jul 2008, 11:05
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# If g(x)=ax^5+bx^3+1, and g(5)=10, then g(-5)=? (A) -10 (B)

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