Debaditya123
Bunuel

If, in the figure above, ABCD is a rectangular region, what is the value of the ratio \(\frac{area \ of \ EDA}{area \ of \ EBC}\) ?
(1) AD = 4
(2) AE = 2 and EB = 4
DS34602.01
OG2020 NEW QUESTION
Attachment:
2019-04-26_1401.png
can the answer not be C?
with st1 we can get AD=BC=4 (since abcd is a rectangle) which are heights of the 2 right-angled triangles resp and from st2 we have AE & BE which are bases of 2 right-angled triangles resp.
then we can find the 2 areas using formula (base*ht)/2
Hi Debaditya123,
We're told that in the figure above, ABCD is a rectangular region. We're asked for the value of the ratio of (area of triangle EDA)/(area of triangle EBC)? This question is based on a couple of Geometry rules. It's worth noting that all 3 triangles (EDA, EBC and EDC) all have the SAME height (so the height of the triangles is actually IRRELEVENT to the question that is asked - as that number will 'cancel out' in the numerator and denominator of the fraction). Thus we ultimately need to know how the two 'bases' of EDA and EBC relate to one another to answer this question.
(1) AD = 4
Fact 1 gives us the height of the triangles, but that does not impact the question at all. The calculation would be:
(1/2)(Base of EDA)(4) / (1/2)(Based of EBC)(4) = ?
(Base of EDA) / (Base of EBC) = ?
Fact 1 is INSUFFICIENT
(2) AE = 2 and EB = 4
Fact 2 gives us the exact lengths of the two 'bases' - and that's all we need to answer the question. The answer would be 2/4 = 1/2
Fact 2 is SUFFICIENT
Final Answer:
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Rich
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