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If integer x were divided by 7, the quotient would be 12 with a remain

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If integer x were divided by 7, the quotient would be 12 with a remain  [#permalink]

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New post 11 Mar 2019, 00:59
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Re: If integer x were divided by 7, the quotient would be 12 with a remain  [#permalink]

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New post 11 Mar 2019, 01:01
Bunuel wrote:
If integer x were divided by 7, the quotient would be 12 with a remainder of 1. Therefore, x equals

A. 91
B. 90
C. 88
D. 85
E. 83



x/7 = 12 + 1

x = 7*12 +1

x = 85.

D is the correct answer.
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Re: If integer x were divided by 7, the quotient would be 12 with a remain  [#permalink]

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New post 12 Mar 2020, 06:17
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Bunuel wrote:
If integer x were divided by 7, the quotient would be 12 with a remainder of 1. Therefore, x equals

A. 91
B. 90
C. 88
D. 85
E. 83


There's a nice rule that says, "If N divided by D equals Q with remainder R, then N = DQ + R"
For example, since 17 divided by 5 equals 3 with remainder 2, then we can write 17 = (5)(3) + 2
Likewise, since 53 divided by 10 equals 5 with remainder 3, then we can write 53 = (10)(5) + 3


Given: If integer x were divided by 7, the quotient would be 12 with a remainder of 1.
Applying the above rule, we get: x = (7)(12) + 1 = 84 + 1 = 85

Answer: D

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Re: If integer x were divided by 7, the quotient would be 12 with a remain  [#permalink]

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New post 15 Mar 2020, 07:23
Bunuel wrote:
If integer x were divided by 7, the quotient would be 12 with a remainder of 1. Therefore, x equals

A. 91
B. 90
C. 88
D. 85
E. 83


We are given that x/7 = 12 R 1, i.e., x/7 = 12 + 1/7. Therefore, multiplying the equation by 7, we have:

x = 84 + 1 = 85

Answer: D
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Re: If integer x were divided by 7, the quotient would be 12 with a remain   [#permalink] 15 Mar 2020, 07:23

If integer x were divided by 7, the quotient would be 12 with a remain

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