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If [a/bc] is defined as being equal to ab – c, then [3/45] + [5/67] is 17 Dec 2020, 04:00
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

5% (low)

Question Stats:

96% (00:51) correct 4% (00:30) wrong based on 56 sessions

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If \([\frac{a.b}{c}]\) is defined as being equal to \(ab – c\), then \([\frac{3.4}{5}] + [\frac{5.6}{7}]\) is equal to

(A) 40
(B) 30
(C) 15
(D) 11
(E) 6
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B
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If [a/bc] is defined as being equal to ab – c, then [3/45] + [5/67] is 17 Dec 2020, 07:08
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Bunuel
If \([\frac{a.b}{c}]\) is defined as being equal to \(ab – c\), then \([\frac{3.4}{5}] + [\frac{5.6}{7}]\) is equal to

(A) 40
(B) 30
(C) 15
(D) 11
(E) 6
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\(\frac{[3.4]}{5}\) = (3*4) - 5 = 12 - 5 = 7

\(\frac{[5.6]}{7}\) = (5*6) - 7 = 30 - 7 = 23


Therefore 23 + 7 = 30


Option B

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If [a/bc] is defined as being equal to ab – c, then [3/45] + [5/67] is 18 Dec 2020, 06:11
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a * b - c:

=> 3 * 4 - 5 = 12 - 5 = 7

=> 5 * 6 - 7 = 30 - 7 = 23

=> 7 + 23 = 30

Answer B
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If [a/bc] is defined as being equal to ab – c, then [3/45] + [5/67] is 18 Dec 2020, 06:54
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\(\frac{[a*b]}{c}\)= a*b-c

\(\frac{[3*4]}{5}\)= 3*4-5 => 12-5 => 7.

\(\frac{[5*6]}{7}\)= 5*6-7 => 30-7 => 23.

Now \(\frac{[3*4]}{5}\)+\(\frac{[5*6]}{7}\)= 23+7 => 30.

Therefore, the OA is B.
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If [a/bc] is defined as being equal to ab – c, then [3/45] + [5/67] is 18 Dec 2020, 10:22
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Bunuel
If \([\frac{a.b}{c}]\) is defined as being equal to \(ab – c\), then \([\frac{3.4}{5}] + [\frac{5.6}{7}]\) is equal to

(A) 40
(B) 30
(C) 15
(D) 11
(E) 6
Show more


\(\frac{[3.4]}{5}\) = \((3*4) - 5 = 12 - 5 = 7\)

\(\frac{[5.6]}{7}\) = \((5*6) - 7 = 30 - 7 = 23\)


So, \(23 + 7 = 30\)

The answer is \(B\)
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If [a/bc] is defined as being equal to ab – c, then [3/45] + [5/67] is 20 Dec 2020, 04:46
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Bunuel
If \([\frac{a.b}{c}]\) is defined as being equal to \(ab – c\), then \([\frac{3.4}{5}] + [\frac{5.6}{7}]\) is equal to

(A) 40
(B) 30
(C) 15
(D) 11
(E) 6
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Solution:

[3.4/5] + [5.6/7]

= (3 x 4 - 5) + (5 x 6 - 7)

= 7 + 23

= 30

Answer: B
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