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VyshakhR1995
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" A "alone is sufficient But with B I am getting a different answer for different value of K .
How D is the answer here.
Thanks
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kannu44
" A "alone is sufficient But with B I am getting a different answer for different value of K .
How D is the answer here.
Thanks

If k is a positive integer, is \((\frac{1}{2})^k > 0.125\)?

Is \((\frac{1}{2})^k > 0.125\)?

Is \((\frac{1}{2})^k > (\frac{1}{2})^3\)?

Is k < 3?

Since given that k is a positive integer, the question basically asks whether k is 1 or 2.

(1) k > 3. Directly gives a NO answer to the question. Sufficient.

(2) \((\frac{1}{2})^{(k-1)} < 0.25\) --> \((\frac{1}{2})^{(k-1)} < (\frac{1}{2})^2\) --> k - 1 > 2 --> k > 3. The same here. Sufficient.

Answer: D.

Hope it helps.
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Thanks Bunuel for your quick response. I was making it too complex but surely your way is much elegant.
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Bunuel
kannu44
" A "alone is sufficient But with B I am getting a different answer for different value of K .
How D is the answer here.
Thanks

If k is a positive integer, is \((\frac{1}{2})^k > 0.125\)?

Is \((\frac{1}{2})^k > 0.125\)?

Is \((\frac{1}{2})^k > (\frac{1}{2})^3\)?

Is k < 3?

Since given that k is a positive integer, the question basically asks whether k is 1 or 2.

(1) k > 3. Directly gives a NO answer to the question. Not sufficient.

(2) \((\frac{1}{2})^{(k-1)} < 0.25\) --> \((\frac{1}{2})^{(k-1)} < (\frac{1}{2})^2\) --> k - 1 > 2 --> k > 3. The same here. Sufficient.

Answer: D.

Hope it helps.

Hello. I did not understand could you please explain, how did the inequality sign change?
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sreeste
Bunuel
kannu44
" A "alone is sufficient But with B I am getting a different answer for different value of K .
How D is the answer here.
Thanks

If k is a positive integer, is \((\frac{1}{2})^k > 0.125\)?

Is \((\frac{1}{2})^k > 0.125\)?

Is \((\frac{1}{2})^k > (\frac{1}{2})^3\)?

Is k < 3?

Since given that k is a positive integer, the question basically asks whether k is 1 or 2.

(1) k > 3. Directly gives a NO answer to the question. Not sufficient.

(2) \((\frac{1}{2})^{(k-1)} < 0.25\) --> \((\frac{1}{2})^{(k-1)} < (\frac{1}{2})^2\) --> k - 1 > 2 --> k > 3. The same here. Sufficient.

Answer: D.

Hope it helps.

Hello. I did not understand could you please explain, how did the inequality sign change?

Consider the following:

Is \((\frac{1}{2})^k > (\frac{1}{2})^3\)

Is \(\frac{1}{2^k} > \frac{1}{2^3}\)

Cross-multiply (notice that we can safely do that since both 2^k and 2^3 are positive): is \(2^3 > 2^k\);

Is \(3 > k\).

The same way with \((\frac{1}{2})^{(k-1)} < (\frac{1}{2})^2\) ;

\(\frac{1}{2^{(k-1)}} < \frac{1}{2^2}\);

\(2^2 < 2^{(k-1)}\)

\(2 < k-1\);

\(3 < k\).

Hope it's clear.
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VyshakhR1995
If k is a positive integer, is \((\frac{1}{2})^k > 0.125\)?

(1) k > 3

(2) \((\frac{1}{2})^{(k-1)} < 0.25\)


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