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Bunuel
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If k is an odd integer, which of the following must be an even integer 28 Oct 2018, 23:45
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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87% (00:55) correct 13% (00:54) wrong based on 173 sessions

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If k is an odd integer, which of the following must be an even integer?


A. \(k^2 – 4\)

B. \(3k + 2\)

C. \(2k + 1\)

D. \(\frac{12k}{8}\)

E. \(\frac{6k}{3}\)
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E
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If k is an odd integer, which of the following must be an even integer 28 Oct 2018, 23:49
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Option E will be 2k. Which will always be even.

E is the answer.
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If k is an odd integer, which of the following must be an even integer 28 Oct 2018, 23:49
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Bunuel
If k is an odd integer, which of the following must be an even integer?


A. \(k^2 – 4\)

B. \(3k + 2\)

C. \(2k + 1\)

D. \(\frac{12k}{8}\)

E. \(\frac{6k}{3}\)
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\(\frac{6k}{3}\) ==> 2K Will be always even

Hence E
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If k is an odd integer, which of the following must be an even integer 29 Oct 2018, 09:10
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Bunuel
If k is an odd integer, which of the following must be an even integer?


A. \(k^2 – 4\)

B. \(3k + 2\)

C. \(2k + 1\)

D. \(\frac{12k}{8}\)

E. \(\frac{6k}{3}\)
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Plug in any value of k and check, let k = 3

(A) 5
(B) 11
(C) 7
(D) 4.5
(E) 6 , Thus Answer must be (E)
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If k is an odd integer, which of the following must be an even integer 29 Oct 2018, 09:55
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Bunuel
If k is an odd integer, which of the following must be an even integer?


A. \(k^2 – 4\)

B. \(3k + 2\)

C. \(2k + 1\)

D. \(\frac{12k}{8}\)

E. \(\frac{6k}{3}\)
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\(\frac{6k}{3}\) --- Will always be even coz 6k/3 is 2K
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If k is an odd integer, which of the following must be an even integer 29 Oct 2018, 17:52
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Bunuel
If k is an odd integer, which of the following must be an even integer?


A. \(k^2 – 4\)

B. \(3k + 2\)

C. \(2k + 1\)

D. \(\frac{12k}{8}\)

E. \(\frac{6k}{3}\)
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A, B, C. Always odd
D. Fraction.
E. 2k. Even.

E!
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If k is an odd integer, which of the following must be an even integer 30 Oct 2018, 19:07
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Bunuel
If k is an odd integer, which of the following must be an even integer?


A. \(k^2 – 4\)

B. \(3k + 2\)

C. \(2k + 1\)

D. \(\frac{12k}{8}\)

E. \(\frac{6k}{3}\)
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Since 6k/3 = 2k and 2k is a multiple of 2, then it must be even.

Answer: E
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If k is an odd integer, which of the following must be an even integer 12 Aug 2020, 13:41
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Bunuel
If k is an odd integer, which of the following must be an even integer?


A. \(k^2 – 4\)

B. \(3k + 2\)

C. \(2k + 1\)

D. \(\frac{12k}{8}\)

E. \(\frac{6k}{3}\)
Show more

The key word in must, which means the correct answer will yield an EVEN value for ALL odd values of k.
So, if we find an odd value for k that does NOT yield an even output, then we can eliminate that answer choice.

Let's see what happens when k = 1 (1 is a nice odd integer to work with)
Plug k = 1 to get...
A. 1² – 4 = -3. -3 is NOT even. ELIMINATE A
B. 3(1) + 2 = 5. 5 is NOT even. ELIMINATE B
C. 2(1) + 1 = 3. 3 is NOT even. ELIMINATE C
D. 12(1)/8 = 3/2. 3/2 is NOT even. ELIMINATE D

By the process of elimination, the correct answer must be E

Cheers,
Brent
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