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If line k is in the xy–coordinate plane, what is the slope of k?

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If line k is in the xy–coordinate plane, what is the slope of k?  [#permalink]

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New post 27 Jul 2018, 03:10
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

91% (00:47) correct 9% (00:50) wrong based on 43 sessions

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If line k is in the xy–coordinate plane, what is the slope of k?  [#permalink]

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New post 27 Jul 2018, 03:18
To find the slope of line k

Statement 1

The x–intercept of k is 3

=> the line k passes through the point (3,0) since y-coordinate is 0 where the line intersects x axis

There are infinite possible lines that can pass through a single point. Some of them have positive slope and some negative slope

Statement 1 is not sufficient

Statement 2

The y–intercept of k is -2

=> the line k passes through the point (0,-2) since x-coordinate is 0 where the line intersects y axis

There are infinite possible lines that can pass through a single point. Some of them have positive slope and some negative slope

Statement 2 is not sufficient

Combining statements 1 and 2

The line k passes through the points (3,0) and (0,-2)

Slope of line k is \(\frac{0-(-2)}{3-0} = \frac{2}{3}\)

Statements 1 and 2 together are sufficient

Hence option C
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Re: If line k is in the xy–coordinate plane, what is the slope of k?  [#permalink]

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New post 27 Jul 2018, 09:37
You need two points to define a line so yeah you need both statements.
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Re: If line k is in the xy–coordinate plane, what is the slope of k?  [#permalink]

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New post 28 Jul 2018, 00:32
1
workout : Answer is C no doubt. Thankyou for the solution.
But the last line is wrong. Slope of a line is (y2-y1)/(x2-x1) so slope will be 2/3
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Re: If line k is in the xy–coordinate plane, what is the slope of k?  [#permalink]

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New post 28 Jul 2018, 00:39
vinitha1595 wrote:
workout : Answer is C no doubt. Thankyou for the solution.
But the last line is wrong. Slope of a line is (y2-y1)/(x2-x1) so slope will be 2/3


Got it. Thank you.
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Re: If line k is in the xy–coordinate plane, what is the slope of k? &nbs [#permalink] 28 Jul 2018, 00:39
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