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Updated on: 15 May 2014, 04:09
Originally posted by steilbergauf on 15 May 2014, 03:44.
Last edited by steilbergauf on 15 May 2014, 04:09, edited 1 time in total.
Last edited by steilbergauf on 15 May 2014, 04:09, edited 1 time in total.
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
70% (01:07) correct
30%
(01:48)
wrong
based on 254
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If m≠0 and \(m-\frac{1+2m^2}{2m} = \frac{y}{m}\), then y is...?
(A) -1
(B) -1/2
(C)-(1+4m^2)
(D) -1+4m^2/2
(E) (2m+1)^2
Can someone please solve this question? I started by multiplying 2m, which didnt lead me anywhere!
(A) -1
(B) -1/2
(C)-(1+4m^2)
(D) -1+4m^2/2
(E) (2m+1)^2
Can someone please solve this question? I started by multiplying 2m, which didnt lead me anywhere!
15 May 2014, 03:54
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steilbergauf
If m≠0 and \(m-\frac{1+2m^2}{2m} = \frac{y}{m}\), then y is...?
Can someone please solve this question? I started by multiplying 2m, which didnt lead me anywhere!
Can someone please solve this question? I started by multiplying 2m, which didnt lead me anywhere!
Hi,
Please put the answer options as well.
Coming back to the question we have
\(m - 1+2m^2/ 2m\)= y/m
So we get (2m^2 -1 -2m^2)/2m = y/m
or y =-1/2
What is the answer ??
15 May 2014, 04:56
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Quote:
Just the answer without the options does not make any sense... Please edit the original post and provide the answer choices. Thank you.
Of course, sorry.
I still dont get it. I solved the question as follows:
m - 1+2m^2/ 2m= y/m (*2m)
2m^2 - 1+2m^2 =ym
4m^2-1 = ym <-- and here I realised Im stuck.
Can you please tell me where I messed it up?!
