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# If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=

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Intern
Joined: 28 Jun 2011
Posts: 12
If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=  [#permalink]

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Updated on: 15 May 2014, 03:09
3
00:00

Difficulty:

35% (medium)

Question Stats:

67% (01:03) correct 33% (01:15) wrong based on 136 sessions

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If m≠0 and $$m-\frac{1+2m^2}{2m} = \frac{y}{m}$$, then y is...?

(A) -1
(B) -1/2
(C)-(1+4m^2)
(D) -1+4m^2/2
(E) (2m+1)^2

Can someone please solve this question? I started by multiplying 2m, which didnt lead me anywhere!

Originally posted by steilbergauf on 15 May 2014, 02:44.
Last edited by steilbergauf on 15 May 2014, 03:09, edited 1 time in total.
Director
Joined: 25 Apr 2012
Posts: 684
Location: India
GPA: 3.21
Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=  [#permalink]

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15 May 2014, 02:54
steilbergauf wrote:
If m≠0 and $$m-\frac{1+2m^2}{2m} = \frac{y}{m}$$, then y is...?

Can someone please solve this question? I started by multiplying 2m, which didnt lead me anywhere!

Hi,

Coming back to the question we have

$$m - 1+2m^2/ 2m$$= y/m

So we get (2m^2 -1 -2m^2)/2m = y/m

or y =-1/2

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Intern
Joined: 28 Jun 2011
Posts: 12
Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=  [#permalink]

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15 May 2014, 03:00
OA is stated, isnt it? Just forgot to put it in the poll. Can I still do this in the editing mode?

Thanks a lot!
Math Expert
Joined: 02 Sep 2009
Posts: 51218
Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=  [#permalink]

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15 May 2014, 03:04
steilbergauf wrote:
OA is stated, isnt it? Just fogot to put it in the poll. Can I still do this in the editing mode?

Thanks a lot!

Just the answer without the options does not make any sense... Please edit the original post and provide the answer choices. Thank you.
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Intern
Joined: 28 Jun 2011
Posts: 12
Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=  [#permalink]

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15 May 2014, 03:56
Quote:
Just the answer without the options does not make any sense... Please edit the original post and provide the answer choices. Thank you.

Of course, sorry.

I still dont get it. I solved the question as follows:

m - 1+2m^2/ 2m= y/m (*2m)
2m^2 - 1+2m^2 =ym
4m^2-1 = ym <-- and here I realised Im stuck.

Can you please tell me where I messed it up?!
Math Expert
Joined: 02 Sep 2009
Posts: 51218
Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=  [#permalink]

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15 May 2014, 05:39
steilbergauf wrote:
Quote:
Just the answer without the options does not make any sense... Please edit the original post and provide the answer choices. Thank you.

Of course, sorry.

I still dont get it. I solved the question as follows:

m - 1+2m^2/ 2m= y/m (*2m)
2m^2 - (1+2m^2) =ym
4m^2-1 = ym <-- and here I realised Im stuck.

Can you please tell me where I messed it up?!

If m≠0 and $$m-\frac{1+2m^2}{2m} = \frac{y}{m}$$, then y is...?

(A) -1
(B) -1/2
(C)-(1+4m^2)
(D) -1+4m^2/2
(E) (2m+1)^2

Multiply both sides by 2m:

$$2m^2-(1+2m^2)= 2y$$ --> $$-1=2y$$ --> $$y=-\frac{1}{2}$$.

Hope it's clear.
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Joined: 09 Sep 2013
Posts: 9166
Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=  [#permalink]

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30 Sep 2018, 05:16
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Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...= &nbs [#permalink] 30 Sep 2018, 05:16
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