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If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=

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If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=  [#permalink]

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New post Updated on: 15 May 2014, 04:09
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  35% (medium)

Question Stats:

65% (01:14) correct 35% (01:47) wrong based on 161 sessions

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If m≠0 and \(m-\frac{1+2m^2}{2m} = \frac{y}{m}\), then y is...?

(A) -1
(B) -1/2
(C)-(1+4m^2)
(D) -1+4m^2/2
(E) (2m+1)^2


Can someone please solve this question? I started by multiplying 2m, which didnt lead me anywhere!

Originally posted by steilbergauf on 15 May 2014, 03:44.
Last edited by steilbergauf on 15 May 2014, 04:09, edited 1 time in total.
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Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=  [#permalink]

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New post 15 May 2014, 03:54
steilbergauf wrote:
If m≠0 and \(m-\frac{1+2m^2}{2m} = \frac{y}{m}\), then y is...?

Can someone please solve this question? I started by multiplying 2m, which didnt lead me anywhere!



Hi,

Please put the answer options as well.


Coming back to the question we have

\(m - 1+2m^2/ 2m\)= y/m

So we get (2m^2 -1 -2m^2)/2m = y/m

or y =-1/2

What is the answer ??
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Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=  [#permalink]

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New post 15 May 2014, 04:00
OA is stated, isnt it? Just forgot to put it in the poll. Can I still do this in the editing mode?

Thanks a lot!
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Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=  [#permalink]

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New post 15 May 2014, 04:04
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Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=  [#permalink]

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New post 15 May 2014, 04:56
Quote:
Just the answer without the options does not make any sense... Please edit the original post and provide the answer choices. Thank you.


Of course, sorry.

I still dont get it. I solved the question as follows:

m - 1+2m^2/ 2m= y/m (*2m)
2m^2 - 1+2m^2 =ym
4m^2-1 = ym <-- and here I realised Im stuck.

Can you please tell me where I messed it up?!
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Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=  [#permalink]

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New post 15 May 2014, 06:39
steilbergauf wrote:
Quote:
Just the answer without the options does not make any sense... Please edit the original post and provide the answer choices. Thank you.


Of course, sorry.

I still dont get it. I solved the question as follows:

m - 1+2m^2/ 2m= y/m (*2m)
2m^2 - (1+2m^2) =ym
4m^2-1 = ym <-- and here I realised Im stuck.

Can you please tell me where I messed it up?!


If m≠0 and \(m-\frac{1+2m^2}{2m} = \frac{y}{m}\), then y is...?

(A) -1
(B) -1/2
(C)-(1+4m^2)
(D) -1+4m^2/2
(E) (2m+1)^2

Multiply both sides by 2m:

\(2m^2-(1+2m^2)= 2y\) --> \(-1=2y\) --> \(y=-\frac{1}{2}\).

Answer: B.

Hope it's clear.
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Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=  [#permalink]

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Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=   [#permalink] 30 Sep 2018, 06:16
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