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If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...=
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steilbergauf
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If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...= [#permalink] New post  Updated on: 15 May 2014, 03:09
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If m≠0 and \(m-\frac{1+2m^2}{2m} = \frac{y}{m}\), then y is...?

(A) -1
(B) -1/2
(C)-(1+4m^2)
(D) -1+4m^2/2
(E) (2m+1)^2


Can someone please solve this question? I started by multiplying 2m, which didnt lead me anywhere!
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Originally posted by steilbergauf on 15 May 2014, 02:44.
Last edited by steilbergauf on 15 May 2014, 03:09, edited 1 time in total.
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Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...= [#permalink] New post  15 May 2014, 02:54
steilbergauf wrote:
If m≠0 and \(m-\frac{1+2m^2}{2m} = \frac{y}{m}\), then y is...?

Can someone please solve this question? I started by multiplying 2m, which didnt lead me anywhere!



Hi,

Please put the answer options as well.

Coming back to the question we have

\(m - 1+2m^2/ 2m\)= y/m

So we get (2m^2 -1 -2m^2)/2m = y/m

or y =-1/2

What is the answer ??
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steilbergauf
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Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...= [#permalink] New post  15 May 2014, 03:00
OA is stated, isnt it? Just forgot to put it in the poll. Can I still do this in the editing mode?

Thanks a lot!
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Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...= [#permalink] New post  15 May 2014, 03:04
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steilbergauf wrote:
OA is stated, isnt it? Just fogot to put it in the poll. Can I still do this in the editing mode?

Thanks a lot!


Just the answer without the options does not make any sense... Please edit the original post and provide the answer choices. Thank you.
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Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...= [#permalink] New post  15 May 2014, 03:56
Quote:
Just the answer without the options does not make any sense... Please edit the original post and provide the answer choices. Thank you.


Of course, sorry.

I still dont get it. I solved the question as follows:

m - 1+2m^2/ 2m= y/m (*2m)
2m^2 - 1+2m^2 =ym
4m^2-1 = ym <-- and here I realised Im stuck.

Can you please tell me where I messed it up?!
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Re: If m ≠ 0 and m - 1+2m^2/2m =y/x, then y is...= [#permalink] New post  15 May 2014, 05:39
Expert Reply
steilbergauf wrote:
Quote:
Just the answer without the options does not make any sense... Please edit the original post and provide the answer choices. Thank you.


Of course, sorry.

I still dont get it. I solved the question as follows:

m - 1+2m^2/ 2m= y/m (*2m)
2m^2 - (1+2m^2) =ym
4m^2-1 = ym <-- and here I realised Im stuck.

Can you please tell me where I messed it up?!


If m≠0 and \(m-\frac{1+2m^2}{2m} = \frac{y}{m}\), then y is...?

(A) -1
(B) -1/2
(C)-(1+4m^2)
(D) -1+4m^2/2
(E) (2m+1)^2

Multiply both sides by 2m:

\(2m^2-(1+2m^2)= 2y\) --> \(-1=2y\) --> \(y=-\frac{1}{2}\).

Answer: B.

Hope it's clear.
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DS: DS Standard deviation | Inequalities | 700+ GMAT Data Sufficiency Questions With Explanations | Tough and tricky exponents and roots questions | The Discreet Charm of the DS | Devil's Dozen!!! | Number Properties set | New DS set
MIXED: GMAT Club's Complete Questions' Bank | SEVEN SAMURAI OF 2012 | Tricky questions from previous years. | Special Questions' Directory | Best Of The Best Of 2017 | The Best Of Quant of 2016 | 20 hardest and 20 best questions of 2015 | 15 best topics of 2015 | Seven Samurai of 2012 | GMAT Probability Questions

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