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If m and n are positive integers and mn = 30, what is the value of m ?

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If m and n are positive integers and mn = 30, what is the value of m ?  [#permalink]

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New post 16 Dec 2017, 01:34
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  35% (medium)

Question Stats:

64% (01:05) correct 36% (00:56) wrong based on 50 sessions

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Re: If m and n are positive integers and mn = 30, what is the value of m ?  [#permalink]

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New post 16 Dec 2017, 01:46
Lets see.
The best course of action is off course a hit and trail.
I would not sit around and make all the pairs of product = 30

Statement 1 ->

(3,10)
(5,6)

Not sufficient
Statement 2 => Hmm
(5,6)
(6,5)


Not sufficient


Combining them up ->

n=5 and m=6

Hence sufficient.


SMASH THAT C.

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Re: If m and n are positive integers and mn = 30, what is the value of m ?  [#permalink]

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New post 16 Dec 2017, 01:48
Bunuel wrote:
If m and n are positive integers and mn = 30, what is the value of m ?

(1) n is an odd prime.
(2) m and n are consecutive integers.


\(mn=30 =>m=\frac{30}{n}\). \(30\) is divisible by \(n\) as \(m\) is a positive integer

Statement 1: \(n\) could be \(3\) or \(5\). so no unique value for \(m\). Insufficient

Statement 2: if \(n=6\), \(m=5\) & if \(n=5\), \(m=6\). No unique value. Insufficient

Combining 1 & 2, we know \(n\) is odd prime. So \(n=5\) & \(m=6\). Sufficient

Option C
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Re: If m and n are positive integers and mn = 30, what is the value of m ?  [#permalink]

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New post 16 Dec 2017, 10:07
Bunuel wrote:
If m and n are positive integers and mn = 30, what is the value of m ?

(1) n is an odd prime.
(2) m and n are consecutive integers.


So, possible solutions for mn (positive integers) = 30 is {30-1,15-2,10-3,6-5}.

(1) n is an odd prime. Then n = 3 and m = 10 or n = 5 and m = 5. Insufficient.

(2) m and n are consecutive integers. Then, m = 6 and n = 5 or m = 5 and n = 6. Insufficient.

(3) Combining both, we know that they are consecutive and that n is an odd prime, so n = 5 and m = 6. Sufficient.

(C) is the answer.
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Re: If m and n are positive integers and mn = 30, what is the value of m ?   [#permalink] 16 Dec 2017, 10:07
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