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Updated on: 24 Apr 2012, 05:25
Originally posted by sagarsabnis on 19 Nov 2009, 14:43.
Last edited by Bunuel on 24 Apr 2012, 05:25, edited 1 time in total.
Last edited by Bunuel on 24 Apr 2012, 05:25, edited 1 time in total.
Edited the question and added the OA
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
67% (01:53) correct
33%
(02:01)
wrong
based on 1338
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If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
(A) 86
(B) 52
(C) 34
(D) 28
(E) 10
(A) 86
(B) 52
(C) 34
(D) 28
(E) 10
19 Nov 2009, 14:56
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Quote:
If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
(A) 86
(B) 52
(C) 34
(D) 28
(E) 10
(A) 86
(B) 52
(C) 34
(D) 28
(E) 10
M = 6p + 1, where p is integer >=0, so M can be 1, 7, 13, etc.
N = 6q + 3, where q is integer >=0, so N can be 3, 9, 15, etc.
M + N = 6(p + q)+4, hence M + N is multiple of 6 plus 4 = 10, 16, 22, 28, 34, etc.
Only answer which is not of this type is 86, 86 = 13*6 + 2.
Answer: A.
Hope it's clear.
General Discussion
19 Nov 2009, 15:31
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but still can you give me the the value of M and N which will add up to 10. If you check the other way round the least numbers are 7 and 9 which adds up to 16 so how come 10 is possible?
