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25 Jul 2018, 11:09
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
77% (00:58) correct
23%
(00:49)
wrong
based on 60
sessions
History
Date
Time
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Not Attempted Yet
If m and n are positive real numbers, is m/n an integer?
(1) n is not an integer.
(2) m is an integer.
(1) n is not an integer.
(2) m is an integer.
25 Jul 2018, 20:05
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To find whether \(\frac{m}{n}\) is an integer or not
m and n are positive real numbers
Statement 1
n is not an integer
case 1, let n = 0.1 and m = 10
=> \(\frac{m}{n} = \frac{10}{0.1} = 100\)
=> \(\frac{m}{n}\) is an integer
case 2, let n = 0.1 and m = 0.01
=> \(\frac{m}{n} = \frac{0.01}{0.1} = 0.1\)
=> \(\frac{m}{n}\) is not an integer
Statement 1 is not sufficient
Statement 2
m is an integer
case 1, let n = 0.1 and m = 10
=> \(\frac{m}{n} = \frac{10}{0.1} = 100\)
=> \(\frac{m}{n}\) is an integer
case 2, let n = 3 and m = 10
=> \(\frac{m}{n} = \frac{10}{3}\) = 3.333
=> \(\frac{m}{n}\) is not an integer
Statement 2 is not sufficient
Combining statements 1 and 2
n is not an integer and m is an integer
case 1, let n = 0.1 and m = 10
=> \(\frac{m}{n} = \frac{10}{0.1} = 100\)
=> \(\frac{m}{n}\) is an integer
case 2, let n = 0.3 and m = 10
=> \(\frac{m}{n} = \frac{10}{3}\) = 3.333
=> \(\frac{m}{n}\) is not an integer
Statements 1 and 2 together are not sufficient
Hence option E
m and n are positive real numbers
Statement 1
n is not an integer
case 1, let n = 0.1 and m = 10
=> \(\frac{m}{n} = \frac{10}{0.1} = 100\)
=> \(\frac{m}{n}\) is an integer
case 2, let n = 0.1 and m = 0.01
=> \(\frac{m}{n} = \frac{0.01}{0.1} = 0.1\)
=> \(\frac{m}{n}\) is not an integer
Statement 1 is not sufficient
Statement 2
m is an integer
case 1, let n = 0.1 and m = 10
=> \(\frac{m}{n} = \frac{10}{0.1} = 100\)
=> \(\frac{m}{n}\) is an integer
case 2, let n = 3 and m = 10
=> \(\frac{m}{n} = \frac{10}{3}\) = 3.333
=> \(\frac{m}{n}\) is not an integer
Statement 2 is not sufficient
Combining statements 1 and 2
n is not an integer and m is an integer
case 1, let n = 0.1 and m = 10
=> \(\frac{m}{n} = \frac{10}{0.1} = 100\)
=> \(\frac{m}{n}\) is an integer
case 2, let n = 0.3 and m = 10
=> \(\frac{m}{n} = \frac{10}{3}\) = 3.333
=> \(\frac{m}{n}\) is not an integer
Statements 1 and 2 together are not sufficient
Hence option E
25 Sep 2024, 06:30
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