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If m and n are positive real numbers, is m/n an integer? (1) n is not

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If m and n are positive real numbers, is m/n an integer? (1) n is not  [#permalink]

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New post 25 Jul 2018, 11:09
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A
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C
D
E

Difficulty:

  25% (medium)

Question Stats:

79% (01:02) correct 21% (00:38) wrong based on 19 sessions

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If m and n are positive real numbers, is m/n an integer?

(1) n is not an integer.

(2) m is an integer.
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Re: If m and n are positive real numbers, is m/n an integer? (1) n is not  [#permalink]

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New post 25 Jul 2018, 20:05
1
To find whether \(\frac{m}{n}\) is an integer or not

m and n are positive real numbers

Statement 1

n is not an integer

case 1, let n = 0.1 and m = 10

=> \(\frac{m}{n} = \frac{10}{0.1} = 100\)

=> \(\frac{m}{n}\) is an integer

case 2, let n = 0.1 and m = 0.01

=> \(\frac{m}{n} = \frac{0.01}{0.1} = 0.1\)

=> \(\frac{m}{n}\) is not an integer

Statement 1 is not sufficient

Statement 2

m is an integer

case 1, let n = 0.1 and m = 10

=> \(\frac{m}{n} = \frac{10}{0.1} = 100\)

=> \(\frac{m}{n}\) is an integer

case 2, let n = 3 and m = 10

=> \(\frac{m}{n} = \frac{10}{3}\) = 3.333

=> \(\frac{m}{n}\) is not an integer

Statement 2 is not sufficient

Combining statements 1 and 2

n is not an integer and m is an integer

case 1, let n = 0.1 and m = 10

=> \(\frac{m}{n} = \frac{10}{0.1} = 100\)

=> \(\frac{m}{n}\) is an integer

case 2, let n = 0.3 and m = 10

=> \(\frac{m}{n} = \frac{10}{3}\) = 3.333

=> \(\frac{m}{n}\) is not an integer

Statements 1 and 2 together are not sufficient

Hence option E
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Re: If m and n are positive real numbers, is m/n an integer? (1) n is not &nbs [#permalink] 25 Jul 2018, 20:05
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