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# If m and n are positive real numbers, is m/n an integer? (1) n is not

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Joined: 22 Aug 2013
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If m and n are positive real numbers, is m/n an integer? (1) n is not  [#permalink]

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25 Jul 2018, 11:09
00:00

Difficulty:

35% (medium)

Question Stats:

80% (00:59) correct 20% (00:33) wrong based on 10 sessions

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If m and n are positive real numbers, is m/n an integer?

(1) n is not an integer.

(2) m is an integer.
RC Moderator
Status: Perfecting myself for GMAT
Joined: 22 May 2017
Posts: 421
Concentration: Nonprofit
Schools: Haas '21
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WE: Engineering (Computer Software)
Re: If m and n are positive real numbers, is m/n an integer? (1) n is not  [#permalink]

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25 Jul 2018, 20:05
1
To find whether $$\frac{m}{n}$$ is an integer or not

m and n are positive real numbers

Statement 1

n is not an integer

case 1, let n = 0.1 and m = 10

=> $$\frac{m}{n} = \frac{10}{0.1} = 100$$

=> $$\frac{m}{n}$$ is an integer

case 2, let n = 0.1 and m = 0.01

=> $$\frac{m}{n} = \frac{0.01}{0.1} = 0.1$$

=> $$\frac{m}{n}$$ is not an integer

Statement 1 is not sufficient

Statement 2

m is an integer

case 1, let n = 0.1 and m = 10

=> $$\frac{m}{n} = \frac{10}{0.1} = 100$$

=> $$\frac{m}{n}$$ is an integer

case 2, let n = 3 and m = 10

=> $$\frac{m}{n} = \frac{10}{3}$$ = 3.333

=> $$\frac{m}{n}$$ is not an integer

Statement 2 is not sufficient

Combining statements 1 and 2

n is not an integer and m is an integer

case 1, let n = 0.1 and m = 10

=> $$\frac{m}{n} = \frac{10}{0.1} = 100$$

=> $$\frac{m}{n}$$ is an integer

case 2, let n = 0.3 and m = 10

=> $$\frac{m}{n} = \frac{10}{3}$$ = 3.333

=> $$\frac{m}{n}$$ is not an integer

Statements 1 and 2 together are not sufficient

Hence option E
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Re: If m and n are positive real numbers, is m/n an integer? (1) n is not &nbs [#permalink] 25 Jul 2018, 20:05
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