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03 Aug 2019, 20:36
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
58% (01:14) correct
42%
(01:30)
wrong
based on 67
sessions
History
Date
Time
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Not Attempted Yet
If m is a positive integer, what is the value of \((5^{3m})(27^{m-5})\)?
(1) \(2^m=32\)
(2) \(m^2-4m=5\)
(1) \(2^m=32\)
(2) \(m^2-4m=5\)
GMATbuster's Collection
03 Aug 2019, 21:34
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Solution as attached.
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WhatsApp Image 2019-08-04 at 10.03.00 AM.jpeg [ 97.9 KiB | Viewed 1568 times ]
03 Aug 2019, 21:55
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(1) 2^m=32
m=5 ---> 5^(3m) * 27^(m−5) can be calculated.
SUFFICIENT
(2) m^2−4m=5
m=-1 or m=5. Since m is positive integer, eliminate m=-1.
m=5 ---> 5^(3m) * 27^(m−5) can be calculated.
SUFFICIENT
Answer is (D)
Posted from my mobile device
m=5 ---> 5^(3m) * 27^(m−5) can be calculated.
SUFFICIENT
(2) m^2−4m=5
m=-1 or m=5. Since m is positive integer, eliminate m=-1.
m=5 ---> 5^(3m) * 27^(m−5) can be calculated.
SUFFICIENT
Answer is (D)
Posted from my mobile device
