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If m is an integer greater than zero but less than integer n [#permalink]
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If m is an integer greater than zero but less than integer n, is m a factor of n? (1) n is divisible by all integers less than 10 (2) m is not a multiple of a prime number
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Originally posted by ananthpatri on 05 Aug 2012, 23:04.
Last edited by Bunuel on 08 Apr 2014, 09:22, edited 3 times in total.
Edited the question and added the OA



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Re: If m is an integer greater than zero but less than n, [#permalink]
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06 Aug 2012, 02:11
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ananthpatri wrote: If m is an integer greater than zero but less than n, is m a factor of n?
(1) n is divisible by all integers less than 10. (2) m is not a multiple of a prime number. (1) n must be divisible by 2, 3, 4,...,9 so, n is divisible by 9! If m = 11, n is not necessarily divisible by m. Not sufficient. (2) m must be 1, therefore m is a factor of n. Sufficient. Answer B
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Re: If m is an integer greater than zero but less than n, [#permalink]
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06 Aug 2012, 20:11
EvaJager wrote: ananthpatri wrote: If m is an integer greater than zero but less than n, is m a factor of n?
(1) n is divisible by all integers less than 10. (2) m is not a multiple of a prime number. (1) n must be divisible by 2, 3, 4,...,9 so, n is divisible by 9! If m = 11, n is not necessarily divisible by m. Not sufficient. (2) m must be 1, therefore m is a factor of n. Sufficient. Answer B What does this mean ? m is not a multiple of a prime number I thought it means that M is a Prime Number itself. Can m be 19 ? How can m be 1 ? 1 is a multiple of one. ? All numbers are a multiple of one. It can then be 2 as well ? 3 as well ? 5 as well ?



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Re: If m is an integer greater than zero but less than n, [#permalink]
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06 Aug 2012, 22:12
mandyrhtdm wrote: EvaJager wrote: ananthpatri wrote: If m is an integer greater than zero but less than n, is m a factor of n?
(1) n is divisible by all integers less than 10. (2) m is not a multiple of a prime number. (1) n must be divisible by 2, 3, 4,...,9 so, n is divisible by 9! If m = 11, n is not necessarily divisible by m. Not sufficient. (2) m must be 1, therefore m is a factor of n. Sufficient. Answer B What does this mean ? m is not a multiple of a prime number I thought it means that M is a Prime Number itself. Can m be 19 ? 19 = 19*1, is a multiple of a prime number 19. So, m cannot be 19. How can m be 1 ? 1 is a multiple of one. ? All numbers are a multiple of one. It can then be 2 as well ? 3 as well ? 5 as well ? 1 is not prime. 2, 3, 5 are primes and all are a multiple of themselves. Neither one can be m. Every positive integer greater than 1 has a unique factorization, meaning it can be written as a product of prime numbers. 1 cannot.
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Re: If m is an integer greater than zero but less than n, [#permalink]
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11 Aug 2012, 04:08
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ananthpatri wrote: If m is an integer greater than zero but less than n, is m a factor of n?
(1) n is divisible by all integers less than 10. (2) m is not a multiple of a prime number. stmt 1: n = LCM(29) * K  INSUFFICIENT stmt 2: m is not a multiple of prime number means, m can not be a composite number, because every composite number can be factorized in to product of prime numbers m can not even be a prime number, because every prime number is a multiple of itself. m has to be an integer greater than 0. only value n can have is 1. coming to root question. is m a factor of n. If m = 1, yes..! As 1 is a multiple of every integer.  SUFFICIENT So answer is B.
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Re: If m is an integer greater than zero but less than n, [#permalink]
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11 Aug 2012, 10:23
I reached the same conclusion hermit84 but then I realized that we are not explicitely told that n is an integer, a condition I think is necessary for statement 2 to be sufficient on its own.
Hence, C (if my assumption holds).



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Re: If m is an integer greater than zero but less than n, [#permalink]
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11 Aug 2012, 10:49
leodesrumaux wrote: I reached the same conclusion hermit84 but then I realized that we are not explicitely told that n is an integer, a condition I think is necessary for statement 2 to be sufficient on its own.
Hence, C (if my assumption holds). The question is about m being a factor of n. The term factor is used only for integers. So, n is also an integer. I agree, it would have been better to state clearly that both m and n are positive integers.
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Re: If m is an integer greater than zero but less than n, [#permalink]
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11 Aug 2012, 10:57
EvaJager wrote: ananthpatri wrote: If m is an integer greater than zero but less than n, is m a factor of n?
(1) n is divisible by all integers less than 10. (2) m is not a multiple of a prime number. (1) n must be divisible by 2, 3, 4,...,9 so, n is divisible by 9! If m = 11, n is not necessarily divisible by m. Not sufficient. (2) m must be 1, therefore m is a factor of n. Sufficient. Answer B hermit84 is right: n must be divisible by the least common multiple of all the integers less than 10, which is not 9! as I stated in my above post. The difference is a factor of \(2^3*3\), so, 9! is not accurate. The rest holds, and doesn't change the conclusion.
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Re: If m is an integer greater than zero but less than n, [#permalink]
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11 Aug 2012, 12:25
leodesrumaux wrote: I reached the same conclusion hermit84 but then I realized that we are not explicitely told that n is an integer, a condition I think is necessary for statement 2 to be sufficient on its own.
Hence, C (if my assumption holds). leodesrumaux, be cautious but not extra cautious. I know there are many DS questions, which will test the same thing you pointed, but not here. n has to be integer, if we are talking about factors here. Even if we assume that every whole number can have a factor, we will still have to accept 1 as a universal factor. I hope it makes sense.
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Re: If m is an integer greater than zero but less than n, [#permalink]
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Updated on: 29 Aug 2012, 18:25
That one is interesting! Read the question stem carefully:
If m is an integer greater than zero but less than n, is m a factor of n? what do we learn?  m is an integer > 0 , m can be 1,2,3,4...................  m must be less than n, n < m, note that we don't know whether n is an integer; we simply know that n is positive Now the question: Is m a factor of n OR is n a multiple of m?
Before tackling the statements, let us give a few conditions that will make n divisible by m: 1 n is an integer, therefore  m=1  m has all the prime factors of n ( so m cannot be prime)
2 n is not an integer, therefore n/m cannot be an integer.
What do the statements reveal or imply ?
1) n is divisible by all intergers less than 10  n is an integer  n is not prime (1,2,3,4........,9 are factors of n) as you may notice, this statement is not sufficient: n is an integer, and is not prime. if m can be written as a product of prime factors less than 10, n/m would be sufficient; but m can be written as a product of prime factors less than 10 and a prime (n = 2*11 =22 or n = 3*17 = 51), and n/m will not necessarily be a integer. Not sufficient
2) m is not a multiple of a prime number this clearly means that m cannot be written as the product of a prime integer therefore m must be 1, since any nonprime can be written as the product of prime integers (2,3,5,7,11,13.....) AND a prime is a multiple of itself
clearly statement (2) is not sufficient n can still be any number (integer, fraction etc.); if n were a fraction n/1 cannot be an integer. for n/m to be an integer, n must be an integer. But statement (2) does not give us enough information about n.
BUT COMBINING THE TWO STATEMENTS IS SUFFICIENT  n is an integer and n can be written as the product of all integers from 2 to 9 (from statement 1)  n< m (from the stem)  m = 1 (statement 2)
Therefore C must the correct answer
Originally posted by silas on 29 Aug 2012, 15:39.
Last edited by silas on 29 Aug 2012, 18:25, edited 1 time in total.



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Re: If m is an integer greater than zero but less than n, [#permalink]
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29 Aug 2012, 15:51
hermit84 wrote: leodesrumaux wrote: I reached the same conclusion hermit84 but then I realized that we are not explicitely told that n is an integer, a condition I think is necessary for statement 2 to be sufficient on its own.
Hence, C (if my assumption holds). leodesrumaux, be cautious but not extra cautious. I know there are many DS questions, which will test the same thing you pointed, but not here. n has to be integer, if we are talking about factors here. Even if we assume that every whole number can have a factor, we will still have to accept 1 as a universal factor. I hope it makes sense. @hermit84 leodesrumaux is right to be cautious or extra cautious. We must not assume anything that is not clearly stated. And in the question stem, it is clearly stated that m is an integer. And they want us to decide whether a number "n" is a multiple of integer m. Even though 1 is a universal factor, n/1 will not be an integer if n is decimal or a fraction. And that is one the the three tricks I noticed with the question Hope this helps



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Re: If m is an integer greater than zero but less than n, [#permalink]
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08 Apr 2014, 09:05
What's the answer for this one? I too thought that it didn't matter whether 'n' was an integer since 1 is a factor of any number whether integer or not. Therefore, IMHO B stands Please let us know will ya? Thanks Cheers J



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Re: If m is an integer greater than zero but less than n, [#permalink]
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08 Apr 2014, 09:26
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jlgdr wrote: What's the answer for this one? I too thought that it didn't matter whether 'n' was an integer since 1 is a factor of any number whether integer or not. Therefore, IMHO B stands Please let us know will ya? Thanks Cheers J Term "factor" is used only for integers. Also, the question was copied incorrectly, actual question says that n is in fact an integer. If m is an integer greater than zero but less than integer n, is m a factor of n?(1) n is divisible by all integers less than 10. Clearly insufficient. (2) m is not a multiple of a prime number. Every positive integer is a multiple of at least one prime number except 1, thus m=1, which implies that it must be a factor of any other integer including n. Sufficient. Answer: B.
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