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If mn≠0, what is the value of m+1/m-n+1/n?

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Math Revolution GMAT Instructor
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If mn≠0, what is the value of m+1/m-n+1/n?  [#permalink]

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New post Updated on: 02 Mar 2017, 04:20
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If mn≠0, what is the value of \(\frac{m+1}{m}-\frac{n+1}{n}\)?

1) m=n
2) m=1

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Originally posted by MathRevolution on 28 Feb 2017, 00:42.
Last edited by Bunuel on 02 Mar 2017, 04:20, edited 1 time in total.
Edited the OA.
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Re: If mn≠0, what is the value of m+1/m-n+1/n?  [#permalink]

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New post 02 Mar 2017, 00:37
==> If you modify the original condition and the question, you get \(\frac{m+1}{m}-\frac{n+1}{n}=\frac{n(m+1)-m(n+1)}{mn}= \frac{nm+n-mn-m}{mn}=\frac{n-m}{mn}=?\). Then, for con 1), m=n, so n-mmn=0, hence it is unique and sufficient.

The answer is A.
Answer: A
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Re: If mn≠0, what is the value of m+1/m-n+1/n?  [#permalink]

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New post 02 Mar 2017, 00:40
1
MathRevolution wrote:
==> If you modify the original condition and the question, you get \(\frac{m+1}{m}-\frac{n+1}{n}=\frac{n(m+1)-m(n+1)}{mn}= \frac{nm+n-mn-m}{mn}=\frac{n-m}{mn}=?\). Then, for con 1), m=n, so n-mmn=0, hence it is unique and sufficient.

The answer is A.
Answer: A


MathRevolution : The correct option is A but the OA marked in the question is B, can you please correct it ?
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Re: If mn≠0, what is the value of m+1/m-n+1/n?  [#permalink]

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New post 02 Mar 2017, 04:21
0akshay0 wrote:
MathRevolution wrote:
==> If you modify the original condition and the question, you get \(\frac{m+1}{m}-\frac{n+1}{n}=\frac{n(m+1)-m(n+1)}{mn}= \frac{nm+n-mn-m}{mn}=\frac{n-m}{mn}=?\). Then, for con 1), m=n, so n-mmn=0, hence it is unique and sufficient.

The answer is A.
Answer: A


MathRevolution : The correct option is A but the OA marked in the question is B, can you please correct it ?


Done. Edited the OA. Thank you.
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Re: If mn≠0, what is the value of m+1/m-n+1/n? &nbs [#permalink] 02 Mar 2017, 04:21
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