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# If n baseball cards costs $3 each, m baseball cards cost$7 each, and

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Math Expert
Joined: 02 Sep 2009
Posts: 47012
If n baseball cards costs $3 each, m baseball cards cost$7 each, and [#permalink]

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25 Dec 2017, 00:46
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Question Stats:

94% (00:36) correct 6% (01:12) wrong based on 16 sessions

If n baseball cards costs $3 each, m baseball cards cost$7 each, and p baseball cards cost $4 each, then the average (arithmetic mean) cost, in dollars per baseball card, is equal to A. 6nmp B. (3n + 7m + 4p)/(nmp) C. (3n + 7m + 4p)/14 D. (3n + 7m + 4p)/(n + m + p) E. 84nmp//(n + m + p) _________________ examPAL Representative Joined: 07 Dec 2017 Posts: 500 Re: If n baseball cards costs$3 each, m baseball cards cost $7 each, and [#permalink] ### Show Tags 25 Dec 2017, 01:28 Bunuel wrote: If n baseball cards costs$3 each, m baseball cards cost $7 each, and p baseball cards cost$4 each, then the average (arithmetic mean) cost, in dollars per baseball card, is equal to

A. 6nmp

B. (3n + 7m + 4p)/(nmp)

C. (3n + 7m + 4p)/14

D. (3n + 7m + 4p)/(n + m + p)

E. 84nmp//(n + m + p)

As calculating the average is often very simple, we'll just do it.
This is a Precise approach to solution.

To calculate the average price per card, we need the total dollar value of all cards divided by the number of cards.
A total of n cards at 3$, m cards at$7 and p cards at $4 were bought. Then the total dollar value is 3n + 7m + 4p and the total number of cards is n + m + p. Dividing these gives (D), our answer. _________________ David Senior tutor at examPAL Signup for a free GMAT course We won some awards: Save up to$250 on examPAL packages (special for GMAT Club members)

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Joined: 24 Nov 2016
Posts: 148
If n baseball cards costs $3 each, m baseball cards cost$7 each, and [#permalink]

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25 Dec 2017, 12:33
Bunuel wrote:
If n baseball cards costs $3 each, m baseball cards cost$7 each, and p baseball cards cost $4 each, then the average (arithmetic mean) cost, in dollars per baseball card, is equal to A. 6nmp B. (3n + 7m + 4p)/(nmp) C. (3n + 7m + 4p)/14 D. (3n + 7m + 4p)/(n + m + p) E. 84nmp//(n + m + p) $$average=\frac{total.cost}{total.cards}$$ = $$\frac{3n+7m+p4}{n+m+p}$$ (D) is the answer. If n baseball cards costs$3 each, m baseball cards cost $7 each, and [#permalink] 25 Dec 2017, 12:33 Display posts from previous: Sort by # If n baseball cards costs$3 each, m baseball cards cost \$7 each, and

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