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If n is a 2digit positive integer and its tens digit is 4 times its u
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06 Aug 2018, 23:59
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[ Math Revolution GMAT math practice question] If n is a 2digit positive integer and its tens digit is 4 times its units digit, what is the value of n? 1) The tens digit of n is 8. 2) The sum of the tens digit and the units digit of n is 2digit integer.
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If n is a 2digit positive integer and its tens digit is 4 times its u
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07 Aug 2018, 00:12
MathRevolution wrote: [ Math Revolution GMAT math practice question] If n is a 2digit positive integer and its tens digit is 4 times its units digit, what is the value of n? 1) The tens digit of n is 8. 2) The sum of the tens digit and the units digit of n is 2digit integer. St1: The tens digit of n is 8. Given, tens digit is 4 times its units digit. So, units digit is \(\frac{8}{4}=2\) Therefore, the 2digit positive integer, n is 82. Sufficient. St2:The sum of the tens digit and the units digit of n is 2digit integer. If units digit is y and tens digit is x, then n=10x+y. n= x y or 4y ySince, x+y is a 2digit integer, we have y=2 as unit digit. So, tens digit=4y=4*2=8. So, n=10x+y=10*8+2=82 Sufficient. Ans. (D)
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Re: If n is a 2digit positive integer and its tens digit is 4 times its u
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07 Aug 2018, 01:45
(1) Tens digit= 8. So Unit digit is \(\frac{8}{4}\)= 2 Value of n=82 [Suff] (2) Only 82 fulfill the condition given in statement 2. Value of n=82 [Suff] Answer: D.
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If n is a 2digit positive integer and its tens digit is 4 times its u
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07 Aug 2018, 06:37
PKN wrote: MathRevolution wrote: [ Math Revolution GMAT math practice question] If n is a 2digit positive integer and its tens digit is 4 times its units digit, what is the value of n? 1) The tens digit of n is 8. 2) The sum of the tens digit and the units digit of n is 2digit integer. St1: The tens digit of n is 8. Given, tens digit is 4 times its units digit. So, units digit is \(\frac{8}{4}=2\) Therefore, the 2digit positive integer, n is 82. Sufficient. St2:The sum of the tens digit and the units digit of n is 2digit integer. If units digit is y and tens digit is x, then n=10x+y. n= x y or 4y ySince, x+y is a 2digit integer, we have y=2 as unit digit. So, tens digit=4y=4*2=8. So, n=10x+y=10*8+2=82 Sufficient. Ans. (D) Hi PKN can you please elaborate on statement TWO St2:The sum of the tens digit and the units digit of n is 2digit integer. If units digit is y and tens digit is x, then n=10x+y. n=x y or 4y y
Since, x+y is a 2digit integer, we have y=2 as unit digit. So, tens digit=4y=4*2=8. So, n=10x+y=10*8+2=82are you using remainder formula ? n=10x+y. X is quotient and Y is remainer ? why ? any other method to explain second statement? you explanation is kinda hard to understand thanks problem solver killer i think your username could be PSK instead of PKN



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Re: If n is a 2digit positive integer and its tens digit is 4 times its u
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07 Aug 2018, 07:11
MathRevolution wrote: [ Math Revolution GMAT math practice question] If n is a 2digit positive integer and its tens digit is 4 times its units digit, what is the value of n? 1) The tens digit of n is 8. 2) The sum of the tens digit and the units digit of n is 2digit integer. A two digit number = ab can also be written as 10a+b (21 =10*2+1) also , a=4b ( as given in the question) 1) The tens digit of n is 8. given a = 8 substituting the value b=2 n=82 suficient 2) The sum of the tens digit and the units digit of n is 2digit integer. a+b= cd a 2 digit number we are already given a=4b the minimum value a can take is 4 when b= 1 but 4+1=5 doesnot satisfy the condition it will satisfy the condition only when b=2 and a=8 so, 8+2= a two digit number D it should be !! realized no need for 10a + b stuff !!



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If n is a 2digit positive integer and its tens digit is 4 times its u
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07 Aug 2018, 07:18
dave13 wrote: PKN wrote: MathRevolution wrote: [ Math Revolution GMAT math practice question] If n is a 2digit positive integer and its tens digit is 4 times its units digit, what is the value of n? 1) The tens digit of n is 8. 2) The sum of the tens digit and the units digit of n is 2digit integer. St1: The tens digit of n is 8. Given, tens digit is 4 times its units digit. So, units digit is \(\frac{8}{4}=2\) Therefore, the 2digit positive integer, n is 82. Sufficient. St2:The sum of the tens digit and the units digit of n is 2digit integer. If units digit is y and tens digit is x, then n=10x+y. n= x y or 4y ySince, x+y is a 2digit integer, we have y=2 as unit digit. So, tens digit=4y=4*2=8. So, n=10x+y=10*8+2=82 Sufficient. Ans. (D) Hi PKN can you please elaborate on statement TWO St2:The sum of the tens digit and the units digit of n is 2digit integer. If units digit is y and tens digit is x, then n=10x+y. n=x y or 4y y
Since, x+y is a 2digit integer, we have y=2 as unit digit. So, tens digit=4y=4*2=8. So, n=10x+y=10*8+2=82are you using remainder formula ? n=10x+y. X is quotient and Y is remainer ? why ? any other method to explain second statement? you explanation is kinda hard to understand thanks problem solver killer i think your username could be PSK instead of PKN what he probably meant was n= 10x+y from question stem x=4y so n= 40y+y



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Re: If n is a 2digit positive integer and its tens digit is 4 times its u
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07 Aug 2018, 07:58
dave13 wrote: PKN wrote: MathRevolution wrote: [ Math Revolution GMAT math practice question] If n is a 2digit positive integer and its tens digit is 4 times its units digit, what is the value of n? 1) The tens digit of n is 8. 2) The sum of the tens digit and the units digit of n is 2digit integer. St1: The tens digit of n is 8. Given, tens digit is 4 times its units digit. So, units digit is \(\frac{8}{4}=2\) Therefore, the 2digit positive integer, n is 82. Sufficient. St2:The sum of the tens digit and the units digit of n is 2digit integer. If units digit is y and tens digit is x, then n=10x+y. n= x y or 4y ySince, x+y is a 2digit integer, we have y=2 as unit digit. So, tens digit=4y=4*2=8. So, n=10x+y=10*8+2=82 Sufficient. Ans. (D) Hi PKN can you please elaborate on statement TWO St2:The sum of the tens digit and the units digit of n is 2digit integer. If units digit is y and tens digit is x, then n=10x+y. n=x y or 4y y
Since, x+y is a 2digit integer, we have y=2 as unit digit. So, tens digit=4y=4*2=8. So, n=10x+y=10*8+2=82are you using remainder formula ? n=10x+y. X is quotient and Y is remainder ? why ? any other method to explain second statement? you explanation is kinda hard to understand thanks problem solver killer i think your username could be PSK instead of PKN Hi dave13, You know ,we can express any number in the following form: 1. 3digit number, XYZ=100X+10Y+Z Example, 123=100*1+10*2+3=100+20+3=123 2. 2digit number, XY=10X+Y Example, 12=10*1+2=10+2=12 In my explanation, I have considered XY, the 2digit positive integer, where X and Y are the tens and units digit respectively. So, as per above algebra form of a 2digit number, we can write n=10*X+Y.(1) Hope you agree. Refer question , it is told that "tens digit is 4 times its units digit." So, X=4*Y(2) In st2, we are told that "the sum of the tens digit and the units digit of n is 2digit integer. Now, kindly refer the enclosure for furtherance. Hope it helps.
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Re: If n is a 2digit positive integer and its tens digit is 4 times its u
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07 Aug 2018, 09:00
many thanks friends PKN and CounterSniper for wonderful explanations



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Re: If n is a 2digit positive integer and its tens digit is 4 times its u
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09 Aug 2018, 00:29
=> Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. \(n = 10a + b\) and \(a = 4b\) The possible pairs \(( a, b )\) are \(( 4, 1 )\) and \(( 8, 2 )\) by the original condition. Thus, \(n = 41\) or \(n = 82\). Since we have \(3\) variables and \(2\) equations, D is most likely to be the answer. So, we should consider each of the conditions on its own first. Condition 1) Since \(a = 8\), we must have \(n = 82\). Thus, condition 1) is sufficient. Condition 2) Since \(4 + 1 = 5\) is not a 2digit integer and \(8 + 2 = 10\) is a 2digit integer, \(n = 82.\) Thus, condition 2) is sufficient. Therefore, D is the answer. Answer: D If the original condition includes “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations” etc., one more equation is required to answer the question. If each of conditions 1) and 2) provide an additional equation, there is a 59% chance that D is the answer, a 38% chance that A or B is the answer, and a 3% chance that the answer is C or E. Thus, answer D (conditions 1) and 2), when applied separately, are sufficient to answer the question) is most likely, but there may be cases where the answer is A,B,C or E.
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