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17 Mar 2023, 10:10
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n^3 – n = (n-1) (n) (n+1) i.e. three consecutive integers.
Statement B: n^2 + n is divisible by 6
n^2 + n = n (n+1) i.e. the product of two positive consecutive integers.
(n^2 + n) can take value which are multiple of 6 i.e. 6, 12, 18, 24, 30.
First Number 6 = 2*3 (the product of two positive consecutive integers).
(n-1) (n) (n+1) = 1 * 2 * 3 is NOT a multiple of 4.
2nd Number 12 = 3*4 (the product of two positive consecutive integers)
(n-1) (n) (n+1) = 2 * 3 * 4 IS a multiple of 4.
Two different answers. Hence, not sufficient.
Statement B: n^2 + n is divisible by 6
n^2 + n = n (n+1) i.e. the product of two positive consecutive integers.
(n^2 + n) can take value which are multiple of 6 i.e. 6, 12, 18, 24, 30.
First Number 6 = 2*3 (the product of two positive consecutive integers).
(n-1) (n) (n+1) = 1 * 2 * 3 is NOT a multiple of 4.
2nd Number 12 = 3*4 (the product of two positive consecutive integers)
(n-1) (n) (n+1) = 2 * 3 * 4 IS a multiple of 4.
Two different answers. Hence, not sufficient.
28 Mar 2025, 10:00
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