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FN
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E

The least factorial where 14 is a factor is 7!, 1 x 2 x 3 x 4 x 5 x 6 x 7, so in order for 14 to be a factor of N!, we know N must be greater than 7.

1) The least value of N would be 4. (N+1)! = 5! = 1 x 2 x 3 x 4 x 5, the smallest number that is also divisible by 15. We know N is greater than or equal to 4 so 1) is a no, eliminate A and D, down to BCE

2) The least value of N would be 6. (N+2)! = 8! = 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8, the smallest number that is also divisible by 16. We know N is greater than or equal to 6 so 2) is a no, elimante B, down to C or E

Combine the two statements and we know N must be greater than 4, which could or could not be greater than 7, eliminate choice C, the answer is E
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I solve this by plugging in numbers.

Ans should be 'E'

for N=4,
5! is div by 15 and 6! is div by 16 but 4! is not div by 14

for N =7,
8! is div by 15 and 9! is div by 16 and 7! is div by 14

So insuff
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Hi Karishma/Bunuel,

Is there any other way apart from plugging in numbers?

I got this in GC CAT.
C looked suspicious so chose E.
but even if we have to plug in numbers, how can we quicky come up with numbers to say a yes and no for both statements combined?
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