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Re: If N is a positive integer, is N! divisible by 14 ? [#permalink]

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09 Apr 2008, 12:23

looks to be E..

(N+2)! =16N basically means we have 2^4 of 2s at a minimum..that means N+2=6 at the least..or N at the least equal 4.. again we cant say anything about N

Re: If N is a positive integer, is N! divisible by 14 ? [#permalink]

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09 Apr 2008, 12:43

E

The least factorial where 14 is a factor is 7!, 1 x 2 x 3 x 4 x 5 x 6 x 7, so in order for 14 to be a factor of N!, we know N must be greater than 7.

1) The least value of N would be 4. (N+1)! = 5! = 1 x 2 x 3 x 4 x 5, the smallest number that is also divisible by 15. We know N is greater than or equal to 4 so 1) is a no, eliminate A and D, down to BCE

2) The least value of N would be 6. (N+2)! = 8! = 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8, the smallest number that is also divisible by 16. We know N is greater than or equal to 6 so 2) is a no, elimante B, down to C or E

Combine the two statements and we know N must be greater than 4, which could or could not be greater than 7, eliminate choice C, the answer is E

Re: If N is a positive integer, is N! divisible by 14 ? [#permalink]

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12 Feb 2013, 02:45

Hi Karishma/Bunuel,

Is there any other way apart from plugging in numbers?

I got this in GC CAT. C looked suspicious so chose E. but even if we have to plug in numbers, how can we quicky come up with numbers to say a yes and no for both statements combined?
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hope is a good thing, maybe the best of things. And no good thing ever dies.

Is there any other way apart from plugging in numbers?

I got this in GC CAT. C looked suspicious so chose E. but even if we have to plug in numbers, how can we quicky come up with numbers to say a yes and no for both statements combined?

If N is a positive integer, is N! divisible by 14 ?

In order n! to be divisible by 14=2*7, n must be at least 7. So, the question basically asks whether \(n\geq{7}\).

(1) (N + 1)! is divisible by 15. In order (n+1)! to be divisible by 15=3*5, n+1 must be at least 5. Thus this statement implies that \(n+1\geq{5}\) --> \(n\geq{4}\). Not sufficient.

(2) (N + 2)! is divisible by 16. In order (n+2)! to be divisible by 16=2^4, n+2 must be at least 6 (6!=2*3*4*5*6=(2^4)*3^2*5). Thus this statement implies that \(n+2\geq{6}\) --> \(n\geq{4}\). Not sufficient.

(1)+(2) From above we have that \(n\geq{4}\). If n=4, then the answer is NO but if n=7 then the answer is YES. Not sufficient.

Re: If N is a positive integer, is N! divisible by 14 ? [#permalink]

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17 Jul 2014, 06:47

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Re: If N is a positive integer, is N! divisible by 14 ? [#permalink]

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12 Apr 2016, 20:27

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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