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If N is a twodigit even integer, is N < 20?
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20 Mar 2014, 02:34
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If N is a twodigit even integer, is N < 20? (1) The product of the digits of N is less than the sum of the digits of N. (2) The product of the digits of N is positive.
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Re: If N is a twodigit even integer, is N < 20?
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20 Mar 2014, 05:01
Mountain14 wrote: I am getting A as answer....
Not sure how C....is OA.. If N is a twodigit even integer, is N < 20?(1) The product of the digits of N is less than the sum of the digits of N. This case is possible only if either digit is 0 or 1. For example, N can be 10, 12, 14, 16, 18, 20, 30, 40, ... So, N can be less as well as greater or equal to 20. Not sufficient. (2) The product of the digits of N is positive. This implies that neither of the digits of N is zero. N still can be be less as well as greater than 20, for example, consider 12 or 22. Not sufficient. (1)+(2) Since neither of the digits of N is zero, then values of N like 20, 30, 40, ... are not possible, thus N is definitely less than 20 (12, 14, 16, 18). Sufficient. Answer: C. Hope it's clear.
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Re: If N is a twodigit even integer, is N < 20?
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20 Mar 2014, 02:35
sanjoo wrote: If N is a twodigit even integer, is N < 20? (1) The product of the digits of N is less than the sum of the digits of N. (2) The product of the digits of N is positive. What if N is 21?? i chose E
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Re: If N is a twodigit even integer, is N < 20?
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20 Mar 2014, 02:58



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Re: If N is a twodigit even integer, is N < 20?
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20 Mar 2014, 04:47
I am getting A as answer.... Not sure how C....is OA..
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Re: If N is a twodigit even integer, is N < 20?
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20 Mar 2014, 05:14
Yes clear... I did some silly mistake Thanks a lot
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Re: If N is a twodigit even integer, is N < 20?
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10 May 2014, 11:56
Target question: Is N < 20?
Statement 1: The product of the digits of N is less than the sum of the digits of N. Under what circumstances is the product of the digits of N less than the sum of the digits? This occurs when one of the digits is either a 0 or a 1. So, for example, N could equal 10, 11, 12, ....,20, 21, ...30, 31, 40, 41, 50, 51etc. BUT the question says that N is EVEN. So, N can be 10, 12, 14, 16, 18, 20, 30, 40, 50, 60, 70, 80, or 90 As you can see, N can be less than 20, or N can be greater than 20 Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: The product of the digits of N is positive. There are several possible values of N. Here are two: Case a: N = 12 (product is less than sum). Here, N is less than 20 Case b: N = 21 (product is less than sum). Here, N is greater than 20 Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined Statement 1 tells us that N = 10, 12, 14, 16, 18, 20, 30, 40, 50, 60, 70, 80, or 90 Statement 2 lets us exclude values of N such that one of the digits is zero (since the product of the digits is zero and zero is not positive) So, if we exclude values of N that have a zero digit, we're left with N = 12, 14, 16 or 18 This means that N is definitely less than 20 Since we can answer the target question with certainty, the combined statements are SUFFICIENT
Answer = C



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Re: If N is a twodigit even integer, is N < 20?
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25 May 2014, 20:31
Bunuel wrote: Mountain14 wrote: I am getting A as answer....
Not sure how C....is OA.. (2) The product of the digits of N is positive. This implies that neither of the digits of N is zero. Hi Bunnel Isn't zero considered a positive integer as well? Thanks



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Re: If N is a twodigit even integer, is N < 20?
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26 May 2014, 00:52



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Re: If N is a twodigit even integer, is N < 20?
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22 Sep 2015, 15:23
Bunuel wrote: Mountain14 wrote: I am getting A as answer....
Not sure how C....is OA.. If N is a twodigit even integer, is N < 20?(1) The product of the digits of N is less than the sum of the digits of N. This case is possible only if either digit is 0 or 1. For example, N can be 10, 12, 14, 16, 18, 20, 30, 40, ... So, N can be less as well as greater or equal to 20. Not sufficient. (2) The product of the digits of N is positive. This implies that neither of the digits of N is zero. N still can be be less as well as greater than 20, for example, consider 12 or 22. Not sufficient. (1)+(2) Since neither of the digits of N is zero, then values of N like 20, 30, 40, ... are not possible, thus N is definitely less than 20 (12, 14, 16, 18). Sufficient. Answer: C. Hope it's clear. when i started to solve the problem, i assumed one of the integers of N is negative as per statement 1. for example N has X and Y if X or Y is negative so statement 1 would be fulfilled. for example X is 2, Y is 4 ==> 2*4 = 8 while summing both of them 2+4 = 2. so statement 1 is not sufficient. statement 2 is not sufficient as well. while combining both statement it would not be sufficient. why did we neglect positive and negative number assumption?



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Re: If N is a twodigit even integer, is N < 20?
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31 May 2016, 12:40
Hi guys,
Can someone help explain why we are not considering negative numbers here? (Product will be + which will be > the sum) so it satisfies the initial condition. if we assume negative, then 1 and 2 both dont tell us anything either?



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If N is a twodigit even integer, is N < 20?
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06 Jun 2018, 08:16
Easier solution  The correct Q indicates that N is positive! N=10B+A with A=0, 2, 4, 6, 8 Yes  B=1 and A=0, 2, 4, 6, 8 No  B>=2 and A=0, 2, 4, 6, 8 (1) AB<A+B Option 1: If B=1 then A<A+1 or 0<1  CHECK Option 2: If B=2 then 2A<A+2 or A<2 therefore A can be 0  CHECK {or if B=5 then 5A<A+5 or A<5/4... leads to A=0} Therefore INSUFFICIENT (2) AB>0 or A≠0 and B≠0 A=2, 4, 6, 8 and B=1, 2, 3... Therefore INSUFFICIENT (1+2) The (2) cancels the Option 2 from (1) therefore SUFFICIENT! Bunuel check




If N is a twodigit even integer, is N < 20? &nbs
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06 Jun 2018, 08:16






