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08 Aug 2018, 09:43
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
73% (01:45) correct
27%
(02:00)
wrong
based on 406
sessions
History
Date
Time
Result
Not Attempted Yet
If n is an integer and \(\sqrt{(n^2-6n+9)}\)=5, which of the following could be the value of \((n + 3)^2\)?
A) –2
B) 1
C) 4
D) 11
E) 64
A) –2
B) 1
C) 4
D) 11
E) 64
08 Aug 2018, 10:00
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CAMANISHPARMAR
\(n^2-6n+9\) can be written as \((n-3)^2\)
Given, \(\sqrt{(n^2-6n+9)}\)=5
Squaring both sides, we have
\(n^2-6n+9=5^2\)
Or, \((n-3)^2=5^2\)
Or, \(|n-3|=5\)
So, n-3=5 or, n-3=-5
So, n=8 or, -2
Now, \((n+3)^2=(-2+3)^2=1^2=1\)
Or, \((n+3)^2=(8+3)^2=11^2=121\) (not in answer options)
Ans. (B)
09 Aug 2018, 03:52
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1. square both sides.
2.find x, which will be either 8 or -2.
3.substitute value, comes either 121 or 1.
4. 1 is correct answer.
2.find x, which will be either 8 or -2.
3.substitute value, comes either 121 or 1.
4. 1 is correct answer.
