MathRevolution wrote:

If n is the product of 3 same prime numbers and 1 different prime number, then how many different factors of n are there?

A. 6

B. 8

C. 9

D. 12

E. 18

For those who haven't seen material in citation below: To find the number of factors of n, the method for the formula* mentioned above is

1. List n's prime factors raised to the correct power. Factors here are

"three same prime numbers and one different prime number..." Just assign values (this formula depends on exponents)

7*7*7*13 is

\(7^313^1\)

2. List the

exponents and add 1 to each

3 (+ 1) = 4

1 (+ 1) = 2

3. Multiply the resultant numbers

4*2 = 8 factors of n, 1 and n included

Answer B

*Bunuel, Finding the Number of Factors of an Integer, at

https://gmatclub.com/forum/math-number- ... 88376.html
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