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If n is the smallest positive integer such that n^3/3920 is 07 Jul 2006, 08:01
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100% (03:41) correct 0% (00:00) wrong based on 4 sessions

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If n is the smallest positive integer such that n^3/3920 is also an integer, what is the sum of the digits of n?

(A) 5 (B) 7 (C) 9 (D) 11 (E) 13



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If n is the smallest positive integer such that n^3/3920 is 07 Jul 2006, 08:08
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is it A? :)
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MA
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If n is the smallest positive integer such that n^3/3920 is 07 Jul 2006, 15:22
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kevincan
If n is the smallest positive integer such that n^3/3920 is also an integer, what is the sum of the digits of n?

(A) 5
(B) 7
(C) 9
(D) 11
(E) 13
Show more


k = (n x n x n) / (2x2x2x2x5x7x7)
k = (n x n x n) / (4^2 x 5 x 7^2)

n should be = (4 x 5 x 7)
so total = 16

am i missing or the question is incorrect??????? :roll: :roll: :roll:

laxi, can you elabroate, pls..
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If n is the smallest positive integer such that n^3/3920 is 07 Jul 2006, 15:31
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MA
kevincan
If n is the smallest positive integer such that n^3/3920 is also an integer, what is the sum of the digits of n?

(A) 5
(B) 7
(C) 9
(D) 11
(E) 13

k = (n x n x n) / (2x2x2x2x5x7x7)
k = (n x n x n) / (4^2 x 5 x 7^2)

n should be = (4 x 5 x 7)
so total = 16
Show more


n = 140
total = 1+4 =5
Need to calculate the sum of digits of n.
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If n is the smallest positive integer such that n^3/3920 is 07 Jul 2006, 15:32
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Indeed n=4*7*5=140

So sum of digits of n is 1+4+0=5

Great work, though. Just read the question more carefully :wink:
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If n is the smallest positive integer such that n^3/3920 is 07 Jul 2006, 19:09
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sgrover
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kevincan
If n is the smallest positive integer such that n^3/3920 is also an integer, what is the sum of the digits of n?

(A) 5
(B) 7
(C) 9
(D) 11
(E) 13

k = (n x n x n) / (2x2x2x2x5x7x7)
k = (n x n x n) / (4^2 x 5 x 7^2)

n should be = (4 x 5 x 7)
so total = 16

n = 140
total = 1+4 =5
Need to calculate the sum of digits of n.
Show more


loosing focus. :twisted: :twisted: :twisted:
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If n is the smallest positive integer such that n^3/3920 is 07 Jul 2006, 22:34
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5 it is.

3920 = 5*4*4*4*7*7

So smallest value for n^3 = 5*5*5*4*4*4*7*7*7
So n = 5*4*7 = 140
Sum of digits = 5



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
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