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Bunuel
If n, m, and p are distinct, five-digit positive integers and if p = n + m, is the thousands digit of p equal to the sum of the thousands digits of n and m?

(1) The tens digit of p is equal to the sum of the tens digits of n and m.

(2) The hundreds digit of p is equal to the sum of the hundreds digits of n and m.

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Bunuel
If n, m, and p are distinct, five-digit positive integers and if p = n + m, is the thousands digit of p equal to the sum of the thousands digits of n and m?

(1) The tens digit of p is equal to the sum of the tens digits of n and m.

(2) The hundreds digit of p is equal to the sum of the hundreds digits of n and m.

If n, m, and p are distinct, five-digit positive integers and if p = n + m, is the thousands digit of p equal to the sum of the thousands digits of n and m?

Let n, m & p be expressed as n1n2n3n4n5, m1m2m3m4m5 & p1p2p3p4p5 respectively.
p1p2p3p4p5 = n1n2n3n4n5 + m1m2m3m4m5

Q. Is p2 = n2 + m2 ?

(1) The tens digit of p is equal to the sum of the tens digits of n and m.
p2 = n2 + m2
Since p2 = n2 + m2; there is no carry over of sum of unit digts; p1 = n1 + m1
Since there is no carry over of sum of tens digits;
p3 = n3 + m3; or p3 +1 = n3 + m3
It is not certain whether p2 = n2 + m2
NOT SUFFICIENT

(2) The hundreds digit of p is equal to the sum of the hundreds digits of n and m.
p3 = n3 + m3
There is no carry over of sum of hundredth digit
p2 = n2 + m2
SUFFICIENT

IMO B
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30% of the people thought the way I thought so I am going to ask this- What if the thousands digits of m and n are 5 or bigger? say 7 and 6? In that case the thousands digit of P is NOT equal to the thousands digit of M + N. (6 + 7 = 13 not 3).
I know it sounds dumb but the question needs to somehow clarify this.
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sumert
30% of the people thought the way I thought so I am going to ask this- What if the thousands digits of m and n are 5 or bigger? say 7 and 6? In that case the thousands digit of P is NOT equal to the thousands digit of M + N. (6 + 7 = 13 not 3).
I know it sounds dumb but the question needs to somehow clarify this.

I thought the same way. My answer remains E!
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Quote:
What if the thousands digits of m and n are 5 or bigger? say 7 and 6? In that case the thousands digit of P is NOT equal to the thousands digit of M + N. (6 + 7 = 13 not 3).

yeah this has to be clarified

47864 m
37135 n
-------
84999 p
====
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anandjoy1022
Quote:
What if the thousands digits of m and n are 5 or bigger? say 7 and 6? In that case the thousands digit of P is NOT equal to the thousands digit of M + N. (6 + 7 = 13 not 3).

yeah this has to be clarified

47864 m
37135 n
-------
84999 p
====


Exactly, mi answe remains E
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