GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 16 Jul 2018, 00:04

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# If no car in 1993 was involved in more than four accidents, what is th

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 47006
If no car in 1993 was involved in more than four accidents, what is th [#permalink]

### Show Tags

28 May 2017, 07:07
00:00

Difficulty:

25% (medium)

Question Stats:

79% (01:27) correct 21% (02:01) wrong based on 43 sessions

### HideShow timer Statistics

If no car in 1993 was involved in more than four accidents, what is the minimum number of cars that could have been in accidents in 1993?

(A) 50 thousand
(B) 60 thousand
(C) 70 thousand
(D) 80 thousand
(E) 90 thousand

_________________
BSchool Forum Moderator
Joined: 26 Feb 2016
Posts: 2933
Location: India
GPA: 3.12
If no car in 1993 was involved in more than four accidents, what is th [#permalink]

### Show Tags

08 Aug 2017, 02:56

To find the minimum number of cars that would be in accidents,
we need to assume maximum cars are involved in exactly four accidents.

Since there are a total of 36*10000 accidents that take place in 1993,
the number of accidents taking place in 1993 is $$\frac{36*10000}{4} = 90$$ thousand(Option E)
_________________

You've got what it takes, but it will take everything you've got

SC Moderator
Joined: 22 May 2016
Posts: 1825
If no car in 1993 was involved in more than four accidents, what is th [#permalink]

### Show Tags

08 Aug 2017, 18:00
Bunuel wrote:

If no car in 1993 was involved in more than four accidents, what is the minimum number of cars that could have been in accidents in 1993?

(A) 50 thousand
(B) 60 thousand
(C) 70 thousand
(D) 80 thousand
(E) 90 thousand

This prompt's lesson: look carefully at the legends.

The uselessness of the second graph should be apparent immediately from its legend "in millions."

Accidents are reported in "teen thousands." Division is necessary, and there are no fractional accidents.

1993 had 360,000 accidents. At four per car, minimum number of cars involved is 90,000.

_________________

In the depths of winter, I finally learned
that within me there lay an invincible summer.

If no car in 1993 was involved in more than four accidents, what is th   [#permalink] 08 Aug 2017, 18:00
Display posts from previous: Sort by

# Events & Promotions

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.