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ArinK2101
why is it that you took out the 7? i don't get how you mathematically solved this, because if you wanted a perfect square for example, you could have taken out -16...so you get 32-16=16(also a square)
Bunuel

Let's rewrite the given expression and complete the square:

\(−p + 10\sqrt{p}- 32\)

\(−(p - 10\sqrt{p} + 25)- 7\)

\(−(\sqrt{p} - 5)^2 - 7\).

Since the square of a number is positive or 0, \(−(\sqrt{p} - 5)^2\) is negative or 0. Hence, to maximize \(−(\sqrt{p} - 5)^2 - 7\), the term \(−(\sqrt{p} - 5)^2\) must be 0, which means √p must be 5. Therefore, p = 5^2, which leads to p = 25.

Answer: E.

We try to equate, \(−p + 10\sqrt{p}- 32=\) to \(a^2 - 2ab + b^2\)

=> \(−(p - 10\sqrt{p} + 32)=\) to \(a^2 - 2ab + b^2\)

We can see that \(a\) can be \(\sqrt{p}\) and \(2ab = 10\sqrt{p}\)

=> \(2*\sqrt{p}*b = 10\sqrt{p}\)

=> b = 5

Now if \(a\) = \(\sqrt{p}\) and \(b = 5\)

We'll have \(b^2\) = \(25\), thus we take out \(-7\)

If it were \(b = 4\), then we could've thought of \(16\) and taken out \(16\).

Hope it helps.
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