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metallicafan
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Location: Peru
Concentration: Finance, SMEs, Developing countries, Public sector and non profit organizations
Schools:Harvard, Stanford, Wharton, MIT & HKS (Government)
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13 Dec 2011, 09:51
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
53% (01:39) correct
47%
(01:18)
wrong
based on 124
sessions
History
Date
Time
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Not Attempted Yet
If p and q are consecutive positive integers, is p a multiple of 3 ?
(1) \(q\) is not a multiple of 3.
(2) \(q - 1\) is not a multiple of 3.
The question is easy; however, I have a doubt in relation to the number 0. Should we consider 0 a multiple of 3? I think we should because a multiple of an integer is that integer multiplied by other integer. So , if 0 is that other integer, \(3 x 0 = 0\); thereofore, 0 is a multiple of 3. In other words, 0 would be a multiple of every number.
But I don't know whether it is the reasoning of the GMAT. Or, do they consider only positive multiples? In other words, they don't consider 0 "the other integer" to create a multiple. If they think in that way, how is the answer for this question affected?
For example, in statement (2), could \(q\) be 1? In that sense, \(q-1\) would be 0, and if they only consider positive multiples, \(q-1\) would not be a multiple of 3.
I know that the answer to my question is not necessary to solve this problem, but I prefer to solve that doubt for future problems.
Thank you!
(1) \(q\) is not a multiple of 3.
(2) \(q - 1\) is not a multiple of 3.
The question is easy; however, I have a doubt in relation to the number 0. Should we consider 0 a multiple of 3? I think we should because a multiple of an integer is that integer multiplied by other integer. So , if 0 is that other integer, \(3 x 0 = 0\); thereofore, 0 is a multiple of 3. In other words, 0 would be a multiple of every number.
But I don't know whether it is the reasoning of the GMAT. Or, do they consider only positive multiples? In other words, they don't consider 0 "the other integer" to create a multiple. If they think in that way, how is the answer for this question affected?
For example, in statement (2), could \(q\) be 1? In that sense, \(q-1\) would be 0, and if they only consider positive multiples, \(q-1\) would not be a multiple of 3.
I know that the answer to my question is not necessary to solve this problem, but I prefer to solve that doubt for future problems.
Thank you!
13 Dec 2011, 10:09
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Good question. 0 is a multiple of 3. Negative numbers can also be multiples of 3.
The set of multiples of 3 is {...-9, -6, -3, 0, 3, 6, 9...}
Typically, questions on the GMAT specifically call out positive multiples.
And by rule, questions that ask about Least Common Multiples (LCMs) refer to the least common positive multiples.
I hope that helps!
The set of multiples of 3 is {...-9, -6, -3, 0, 3, 6, 9...}
Typically, questions on the GMAT specifically call out positive multiples.
And by rule, questions that ask about Least Common Multiples (LCMs) refer to the least common positive multiples.
I hope that helps!
metallicafan
Retired Moderator
Joined: 04 Oct 2009
Last visit: 26 Aug 2020
Posts: 755
Own Kudos:
Given Kudos: 109
Status:2000 posts! I don't know whether I should feel great or sad about it! LOL
Location: Peru
Concentration: Finance, SMEs, Developing countries, Public sector and non profit organizations
Schools:Harvard, Stanford, Wharton, MIT & HKS (Government)
GPA: 4.0
WE 1: Economic research
WE 2: Banking
WE 3: Government: Foreign Trade and SMEs
13 Dec 2011, 10:19
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bhavinp
Thank you bhavnip!, kudos for you
So, if this question were in the real exam, I should think that 0 is a multiple of 3, right?
