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04 Oct 2018, 03:40
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
62% (01:53) correct
38%
(01:56)
wrong
based on 111
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If p and q are positive integers, is q odd?
(1) 2p+3q=12
(2) 4p/5q is an odd integer
(1) 2p+3q=12
(2) 4p/5q is an odd integer
Updated on: 04 Oct 2018, 08:13
Originally posted by Salsanousi on 04 Oct 2018, 04:54.
Last edited by Salsanousi on 04 Oct 2018, 08:13, edited 1 time in total.
Last edited by Salsanousi on 04 Oct 2018, 08:13, edited 1 time in total.
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a70
p and q > 0
1) \(2p+3q = 12\) this also comes down to \(p + \frac{3q}{2} = \frac{12}{2}\)
\(p + \frac{3q}{2} = 6\)
q must be a multiple of 2 to get an integer number. So it is not ODD
Sufficient
2) \(\frac{4p}{5q}\) = odd integer
\(\frac{4}{5} * \frac{p}{q}\) this means P must be an odd multiple of 5 and q must be a multiple of 4
(4/5) * (15/4) = 3 odd integer
(4/5) * (5/4) = 1 odd integer
Meaning q must be even. so it is sufficient to say q is NOT ODD
Sufficient
D is the answer choice
04 Oct 2018, 06:10
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a70
\(p,q\,\, \ge 1\,\,{\rm{ints}}\,\,\,\left( * \right)\)
\(q\,\,\mathop = \limits^? \,\,{\rm{odd}}\)
\(\left( 1 \right)\,\,\,2p + 3q = 12\,\,\,\,\,\mathop \Rightarrow \limits^{\left( {**} \right)} \,\,\,\,\left\langle {{\rm{NO}}} \right\rangle\)
\(\left( {**} \right)\,\,q\,\,{\rm{odd}}\,\,\,\mathop \Rightarrow \limits^{\left( * \right)} \,\,\,\,\left( {12 = } \right)\,\,2p + 3q\,\,{\rm{odd}}\,\,{\rm{,}}\,\,\,{\rm{impossible}}\)
\(\left( 2 \right)\,\,\,{{4p} \over {5q}} = {\rm{odd}}\,\,\,\,\, \Rightarrow \,\,\,4p = 5q \cdot {\rm{odd}}\,\,\,\,\,\mathop \Rightarrow \limits^{\left( {***} \right)} \,\,\,\,\left\langle {{\rm{NO}}} \right\rangle\)
\(\left( {***} \right)\,\,\,q\,\,{\rm{odd}}\,\,\,\mathop \Rightarrow \limits^{\left( * \right)} \,\,\,\,\,\left( {4p = } \right)\,\,5q \cdot {\rm{odd}}\,\,{\rm{ = }}\,\,{\rm{odd}}\,\,{\rm{,}}\,\,\,{\rm{impossible}}\,\)
The correct answer is therefore (D).
This solution follows the notations and rationale taught in the GMATH method.
Regards,
Fabio.
