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Bunuel
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If p is a positive integer, Is integer m a multiple of 6? 06 Dec 2016, 00:46
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25% (medium)

Question Stats:

77% (01:20) correct 23% (01:27) wrong based on 142 sessions

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If p is a positive integer, Is integer m a multiple of 6?

(1) 3p + 3 = m
(2) 7! + 3 = m
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B
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If p is a positive integer, Is integer m a multiple of 6? 06 Dec 2016, 01:52
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P=m/3-1 p is a positive interger..So m is multmultiple of 3...but not necessarily multiple of 6...NO

3 (7×6×5×4×2 + 1) = m. Again m is multiple of 3. Same as above.

E.

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If p is a positive integer, Is integer m a multiple of 6? 06 Dec 2016, 01:54
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Sorry auto correct *NO is NS

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If p is a positive integer, Is integer m a multiple of 6? 06 Dec 2016, 01:59
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Here is my solution to this one ->

Given info -->
p and m are integers.
We are asked if m is multiple of 6 or not.

Statement 1 -->
if p=1 => m is divisible by 6
if p=2 => m is not divisible by 6

hence not sufficient

Statement 2-->
m=7!+3
m=6k+3 for some integer k
Hence it will leave a remainder 3 when divide by 6.
Hence m is not divisible by 6.

Hence Sufficient

Hence B
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If p is a positive integer, Is integer m a multiple of 6? 06 Dec 2016, 04:15
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Bunuel
If p is a positive integer, Is integer m a multiple of 6?

(1) 3p + 3 = m
(2) 7! + 3 = m

FROM 1

m is a multiple of 3 and should we know p is odd then m is a multiple of 6 which is not provided ... insuff

from 2

7! is even+ odd = odd , thus m is odd then definitely m is not a multiple of 6 ( even) ... suff

B
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Bunuel
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