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28 Sep 2013, 09:31
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
73% (01:38) correct
27%
(02:00)
wrong
based on 228
sessions
History
Date
Time
Result
Not Attempted Yet
TirthankarP
Joined: 29 Apr 2013
Last visit: 10 Jan 2016
Posts: 81
Given Kudos: 53
Location: India
Concentration: General Management, Strategy
Schools: PGDM (GM) '15 (A)
GMAT Date: 11-06-2013
WE:Programming (Telecommunications)
28 Sep 2013, 09:59
Kudos
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If p is a positive integer, is p + 2 > q?
(1) \(q^2\) > p
(2) q - p < 0
Statement 1: \(q^2\) is always positive irrespective of whether q is positive or negative. So let's plugin values:
q=-2 and p=1
\(q^2\) = 4 --> 4 > 1
p+2 = 1 + 2 = 3 ---> 3 > -2 --> p+2 > q
Again, q = 4, p = 1
\(q^2\) = 16 --> 16 > 1
p+2 = 1 + 2 = 3 ---> 3 is not greater than 4 --> (p+2) not greater than q. So statement 1 alone is insufficient.
Statement 2:
q - p < 0
q < p or p > q
As p is a positive integer, so if p > q then p+2 is definitely greater than q. So statement 2 alone is sufficient.
So Answer B
(1) \(q^2\) > p
(2) q - p < 0
Statement 1: \(q^2\) is always positive irrespective of whether q is positive or negative. So let's plugin values:
q=-2 and p=1
\(q^2\) = 4 --> 4 > 1
p+2 = 1 + 2 = 3 ---> 3 > -2 --> p+2 > q
Again, q = 4, p = 1
\(q^2\) = 16 --> 16 > 1
p+2 = 1 + 2 = 3 ---> 3 is not greater than 4 --> (p+2) not greater than q. So statement 1 alone is insufficient.
Statement 2:
q - p < 0
q < p or p > q
As p is a positive integer, so if p > q then p+2 is definitely greater than q. So statement 2 alone is sufficient.
So Answer B
29 Sep 2013, 12:09
Kudos
Bookmarks
If p is a positive integer, is p + 2 > q?
(1) q^2 > p. If p=1 and q=100, then p+2<q but if p=1 and q=-100, then p+2>q. Not sufficient.
(2) q - p < 0 --> p>q. Since p is greater than q, then p+2 (greater number than p) is also greater than q. Sufficient.
Answer: B.
(1) q^2 > p. If p=1 and q=100, then p+2<q but if p=1 and q=-100, then p+2>q. Not sufficient.
(2) q - p < 0 --> p>q. Since p is greater than q, then p+2 (greater number than p) is also greater than q. Sufficient.
Answer: B.
