Last visit was: 18 May 2026, 15:46 It is currently 18 May 2026, 15:46
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
mrdlee23
Joined: 29 Jan 2017
Last visit: 02 Dec 2018
Posts: 31
Own Kudos:
41
 [9]
Given Kudos: 13
Posts: 31
Kudos: 41
 [9]
Kudos
Add Kudos
9
Bookmarks
Bookmark this Post
User avatar
amanvermagmat
User avatar
Retired Moderator
Joined: 22 Aug 2013
Last visit: 28 Mar 2025
Posts: 1,142
Own Kudos:
Given Kudos: 480
Location: India
Posts: 1,142
Kudos: 2,989
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 18 May 2026
Posts: 110,678
Own Kudos:
Given Kudos: 106,295
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 110,678
Kudos: 815,597
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
Hreeman
Joined: 21 Nov 2017
Last visit: 19 Sep 2018
Posts: 1
Own Kudos:
1
 [1]
Posts: 1
Kudos: 1
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
amanvermagmat
(1) p is n% of n, this means p = n/100 * n = (n^2)/100
Here n is a positive integer, so n^2 is a perfect square. And n^2 must be divisible by 100, because then only p will be an integer. Now if we take square root both sides, we have
√p = √(n^2)/ √100 = n/10
Since n^2 is divisible by 100, this means n must be divisible by 10. So √p is an integer. Sufficient.

(2) p is divisible by 100.
If p = 400, then √p = 20 is an integer.
If p = 300, then √p = 10 √3, is not an integer. So Insufficient.

Hence A answer

Why are we not considering -n/10 as a possible root of n^2/100, in which case p would be negative and give a NO to the "is p a positive integer" question?

That would make Statement 1 insufficient.
User avatar
exc4libur
Joined: 24 Nov 2016
Last visit: 22 Mar 2022
Posts: 1,679
Own Kudos:
Given Kudos: 607
Location: United States
Posts: 1,679
Kudos: 1,473
Kudos
Add Kudos
Bookmarks
Bookmark this Post
mrdlee23
If p is a positive integer is √p a positive integer?

1) p is n percentage of n where n is a positive integer
2) p/100 is a positive integer

p=integer… is p=perfect.square?

1) p is n percentage of n where n is a positive integer sufic.

\((n,p)=integer:p=\frac{n/100}{n}…p=\frac{n^2}{100}…p=\frac{n^2}{10^2}=integer=perf.square\)

2) p/100 is a positive integer insufic.

\(p/100=integer…p=100k…p=(700≠perf.square;100=perf.square)\)

Answer (A)
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 39,096
Own Kudos:
Posts: 39,096
Kudos: 1,125
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
110678 posts
498 posts
264 posts