rishabh195
sjuniv32
If \(p\) is a positive integer less than\( 70\), and \(71^2 − 142p + p^2\) is divisible by \(49\), what is the remainder when \(p\) is divided by \(7\)?
A) 0
B) 1
C) 2
D) 4
E) 6
I am not getting the answer as B. Please help
I am getting the value of p as 70, but because the value of p is less than 70..... I took it as 69 and when 69 divided by 7, it gives a remainder of 6.
But as per the OA, it should give the remainder of 1.
Where am I going wrong? Please help
Posted from my mobile deviceHow are you getting the value of P as 70, can you explain?
Here's how I went about it-
Given: 71^2 - 142p + p^2 is divisible by 49, which means, 71^2 - 142p + p^2 = 49k ---------(1)
If you rearrange 71^2 - 142p + p^2 , you can write it in the form of (a-b)^2.
That will be- (71 - p)^2
Using (1) above,
(71 - p)^2 = 49k
49k can be written as (7K)^2. Since the left side of the equation is a perfect square, the right side should be also a perfect square.
Equating both sides, you would get->
-> 71 - p = 7K
-> p = 71 - 7k
Now, the question is, what is the remainder when p is divided by 7.
-> 71/7 - 7K/7. Here, 7K/7 would yield no remainder. But 71/7 would yield a remainder of 1.
Hence, the option B is correct.