Probus
If P is sequence of n positive integers,where Se denotes the sum of all even integers and So denotes the sum of all odd integers. What is the the value of |Se -So|?
(A) P is a sequence of n consecutive positive integers
(B) Number of terms in the sequence P is 8
1) P is a sequence of n positive integers and from 1) we know that they are consecutive but we don't know if number of terms i.e. n is even or odd and the value of n, therefore we cant solve the question.
We need whether n is Even or odd because of the following reason:
let the first Odd number is O and first even number is E, we can model the sum as
|E-O|+|(E+1)-(O+1)|+|(E+2)-(O+2)|... where we can see that each number is equal to 1 as the difference between first consecutive Even and odd number is 1.Therefore, if n is even, |Se-So|=n/2. But if n is odd then the sum is |(n-1)/2+-last number| and as we don't know the last number we cant solve it.
As we need numerical value of |Se-So|, we need the value of n as well.
Insufficient.2) N is 8, but it is not given how many O and E are there.
Therefore, Insufficient.Combining 1) and 2) we get the answer as n/2 i.e. 4. Sufficient.Please note that this is a DS question, and we need not calculate everything to solve the question; We just need to get the reasoning straight. I solved this question in 1 min 43sec (without pen/paper), using the logic explained above.