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09 Jun 2021, 07:30
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
70% (01:40) correct
30%
(01:44)
wrong
based on 139
sessions
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If pipe B fills a container at a constant rate in 100 minutes, how many minutes does it take pipe A, working at is own constant rate, to fill the same container?
(1) Pipe A and pipe B together fill the container at (1/4) the time it takes pipe A alone.
(2) Pipe A and pipe B together fill the container at (3/4) the time it takes pipe B alone.
(1) Pipe A and pipe B together fill the container at (1/4) the time it takes pipe A alone.
(2) Pipe A and pipe B together fill the container at (3/4) the time it takes pipe B alone.
09 Jun 2021, 10:02
Kudos
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If pipe B fills a container at a constant rate in 100 minutes, how many minutes does it take pipe A, working at is own constant rate, to fill the same container?
(1) Pipe A and pipe B together fill the container at (1/4) the time it takes pipe A alone.
Give a relation between the two pipes with only one's known time.
INSUFFICIENT.
(2) Pipe A and pipe B together fill the container at (3/4) the time it takes pipe B alone.
Gives a relation between two pipes with known time value of pipe B.
SUFFICIENT.
Answer B.
(1) Pipe A and pipe B together fill the container at (1/4) the time it takes pipe A alone.
Give a relation between the two pipes with only one's known time.
INSUFFICIENT.
(2) Pipe A and pipe B together fill the container at (3/4) the time it takes pipe B alone.
Gives a relation between two pipes with known time value of pipe B.
SUFFICIENT.
Answer B.
09 Jun 2021, 10:53
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Bunuel
4 pipes like A, working together, would fill the container in 1/4 of the time it takes one pipe like A. So if A and B together also take 1/4 of the time it takes A alone, then pipe B is exactly like 3 pipes of type A, so pipe B is 3 times faster than pipe A, and pipe A therefore takes 3 times as long as pipe B. So from Statement 1, pipe A takes 300 minutes. Or you could let t represent the time A and B take together, so 4t is the time it takes A alone, and plug into the rates formula, to get 1/100 + 1/4t = 1/t, which becomes a one-variable equation we can solve to find 300 = 4t (which is A's time alone). So Statement 1 is sufficient.
Statement 2 is also sufficient because we then know it takes A 100 minutes alone, it takes A and B 3/4 of that, or 75 minutes together, from which we can work out B's time alone using any standard rates method. So the answer is D.
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