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If r and s are integers, is r^2+s even?

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If r and s are integers, is r^2+s even?  [#permalink]

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New post 02 Nov 2018, 03:46
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Question Stats:

76% (00:46) correct 24% (00:43) wrong based on 39 sessions

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Re: If r and s are integers, is r^2+s even?  [#permalink]

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New post 02 Nov 2018, 04:05
carcass wrote:
If r and s are integers, is \(r^2+s\) even?

(1) The product of rs is odd.
(2) r is odd.


Questions involving number properties are usually based on logic, not explicit calculations.
We'll look for such an answer, a Logical approach.

(1) rs is odd implies that both r and s are odd. Then r^2 is odd and r^2 + s is odd + odd = even.
Sufficient.

(2) without information on s, this is insufficient.
Insufficient.

(A) is our answer.
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Re: If r and s are integers, is r^2+s even?   [#permalink] 02 Nov 2018, 04:05
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If r and s are integers, is r^2+s even?

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