Bunuel wrote:
Bumping for review and further discussion.
If r and s are negative, is r/s less than 1 ?
(1) r + 2s = s^2/r
(2) r/s is 2 less than s/r
(1) r + 2s - (s^2/r)=0
r^2-s^2=-2rs taking RHS part since r & s are -ve then -2rs must be negative
so r^2-s^2<0
r^2<s^2
taking root both sides IrI<IsI
as both are -ve so IrI=-r & IsI=-s
So, now we can write as -r<-s------> r>s
so r/s is always <1
eg. say r=-2 & s=-3 (as r>s and both are -ve)
now -2/-3 < 1
So suff..
(2) r/s is 2 less than s/r
r/s=s/r-2
rearranging we again get r^2-s^2=-2rs
similar reasoning as (1).
Suff..
Ans D