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01 Nov 2018, 00:20
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
61% (01:39) correct
39%
(01:42)
wrong
based on 84
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01 Nov 2018, 00:56
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Bunuel
If R = M/N, is R ≤ M?
(1) M > 40
(2) 0 < N ≤ 15
(1) M > 40
(2) 0 < N ≤ 15
R = M/N can we re-written as...
R*N = M
Now, if N = 1 -> R = M.
N>1 -> R <M ... ( R multiplied by something larger than 1 is equal to M means R was less than M to begin with)
So for R ≤ M -> N >= 1
St1. Not sufficient as no info about N.
St2. Not sufficient as N could be less than 1 or greater than 1.
(1) + (2) together gives no more information.
Hence, Option (E) is our choice.
Best,
Gladi
02 Nov 2018, 07:45
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Statement 1) Let's take M as 45.
R = \(\frac{45}{N}\)
If N = 1, then R = 45 --> \(R\leq{M}\) --> True
If N = \(\frac{1}{3}\), then R = 130 --> \(R\leq{M}\) --> Not True. INSUFFICIENT
Statement 2) No M value. So clearly INSUFFICIENT
1) + 2) Both the values of N = 1 and \(\frac{1}{3}\) fall in the range of \(0<N\leq{15}\). Still we dont have a unique answer.
OPTION : E
R = \(\frac{45}{N}\)
If N = 1, then R = 45 --> \(R\leq{M}\) --> True
If N = \(\frac{1}{3}\), then R = 130 --> \(R\leq{M}\) --> Not True. INSUFFICIENT
Statement 2) No M value. So clearly INSUFFICIENT
1) + 2) Both the values of N = 1 and \(\frac{1}{3}\) fall in the range of \(0<N\leq{15}\). Still we dont have a unique answer.
OPTION : E
