JAI HIND
If S is the sum of the reciprocals of the consecutive integers from 91 to 100, inclusive, which of the following is less than S?
I. 1/8
II. 1/9
III. 1/10
A. None
B. I only
C. III only
D. II and III only
E. I, II, and III
The more is the value of the denominator , the lesser is the value of the fraction.
For ex :- 1/2 > 1/3 ...1/2 means 50%.... 1/3 means 33.33%...
Now here , 1/90 > 1/91
1/90 > 1/92..
.................
10 / 90 > 1/91 + 1/92 + ........1/100
Since each of the term on the left hand side i.e 1/90 is greater than the each of the term on the right hand side ....
So 1/9 > S..
Now , 1/8 > 1/9 ...So 1/8 is also greater than S.
Only one option is left . Option 3 is the answer.
Now lets check why option 3 is the answer.
1/100 < 1/91
1/100 < 1/92
..................
10/100 < 1/91 + 1/92 + ........1/100
1/10 < S