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If S, P, T are there such that s<p<t, is the average (Arithmetic mean)

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If S, P, T are there such that s<p<t, is the average (Arithmetic mean) [#permalink]

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New post Updated on: 13 Feb 2017, 01:46
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If S, P, T are there such that s<p<t, is the average (Arithmetic mean) of s and t equal to 5p/2?

(1) the average of s, p, and t is equal to twice of the median of them.
(2) s + t = 5p

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Originally posted by nahid78 on 15 Jan 2017, 16:24.
Last edited by nahid78 on 13 Feb 2017, 01:46, edited 1 time in total.
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Re: If S, P, T are there such that s<p<t, is the average (Arithmetic mean) [#permalink]

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New post 15 Jan 2017, 19:57
nahid78 wrote:
If S, P, T are there such that s<p<t, is the average (Arithmetic mean) of s and t equal to 5p/2?

(1) the average of s, p, and t is equal to twice of the median of them.
(2) s + t = 5p


Question can be reworded as (s+t)/2=5p/2
or s+t=5P ??

(1) (s+p+t)/3 = 2P( as median =p of s<p<t)
or s+p+t=6p
s+t=5p....suff

(2) directly gives relation
suff

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Re: If S, P, T are there such that s<p<t, is the average (Arithmetic mean) [#permalink]

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New post Updated on: 13 Feb 2017, 01:43
nahid78 wrote:
If s, p, t are there such that \(s<p<t\), is the average (Arithmetic mean) of \(s\) and \(t\) equal to \(\frac{5p}{2}\)?

(1) the average of \(s\), \(p\), and \(t\) is equal to twice of the median of them.
(2) \(s + t = 5p\)


Dear nahid78, What is the official answer for this question?

(1) \(Average =\) \(\frac{(s + p + t)}{3} = 2p\), \(s+p+t=6p\), \(s+t=5p\), \(\frac{s+t}{2} = \frac{5p}{2}\) . Sufficient.

(2) \(s+t=5p\), \(\frac{(s+t)}{2} = \frac{5p}{2}\). Sufficient.

Answer = D
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Originally posted by hazelnut on 12 Feb 2017, 20:02.
Last edited by hazelnut on 13 Feb 2017, 01:43, edited 2 times in total.
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Re: If S, P, T are there such that s<p<t, is the average (Arithmetic mean) [#permalink]

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New post 13 Feb 2017, 01:11
nahid78 wrote:
If S, P, T are there such that s<p<t, is the average (Arithmetic mean) of s and t equal to 5p/2?

(1) the average of s, p, and t is equal to twice of the median of them.
(2) s + t = 5p



D.

S+t/2 = 5p/2 --given ...we need to get s + t =5p

A--- s+p+t/3 =3p
=s+t = 5p --suff

B--s+t =5p --suff ...

hence D.
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Re: If S, P, T are there such that s<p<t, is the average (Arithmetic mean) [#permalink]

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New post 13 Feb 2017, 01:48
Dear ziyuenlau,

you have solved it perfectly. :)
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Re: If S, P, T are there such that s<p<t, is the average (Arithmetic mean)   [#permalink] 13 Feb 2017, 01:48
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