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# If S, P, T are there such that s<p<t, is the average (Arithmetic mean)

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Manager
Joined: 12 Mar 2013
Posts: 240
If S, P, T are there such that s<p<t, is the average (Arithmetic mean)  [#permalink]

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Updated on: 13 Feb 2017, 00:46
00:00

Difficulty:

15% (low)

Question Stats:

75% (01:18) correct 25% (01:35) wrong based on 100 sessions

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If S, P, T are there such that s<p<t, is the average (Arithmetic mean) of s and t equal to 5p/2?

(1) the average of s, p, and t is equal to twice of the median of them.
(2) s + t = 5p

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Originally posted by nahid78 on 15 Jan 2017, 15:24.
Last edited by nahid78 on 13 Feb 2017, 00:46, edited 1 time in total.
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Posts: 1003
Re: If S, P, T are there such that s<p<t, is the average (Arithmetic mean)  [#permalink]

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15 Jan 2017, 18:57
nahid78 wrote:
If S, P, T are there such that s<p<t, is the average (Arithmetic mean) of s and t equal to 5p/2?

(1) the average of s, p, and t is equal to twice of the median of them.
(2) s + t = 5p

Question can be reworded as (s+t)/2=5p/2
or s+t=5P ??

(1) (s+p+t)/3 = 2P( as median =p of s<p<t)
or s+p+t=6p
s+t=5p....suff

(2) directly gives relation
suff

Ans D
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Location: Malaysia
Re: If S, P, T are there such that s<p<t, is the average (Arithmetic mean)  [#permalink]

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Updated on: 13 Feb 2017, 00:43
nahid78 wrote:
If s, p, t are there such that $$s<p<t$$, is the average (Arithmetic mean) of $$s$$ and $$t$$ equal to $$\frac{5p}{2}$$?

(1) the average of $$s$$, $$p$$, and $$t$$ is equal to twice of the median of them.
(2) $$s + t = 5p$$

Dear nahid78, What is the official answer for this question?

(1) $$Average =$$ $$\frac{(s + p + t)}{3} = 2p$$, $$s+p+t=6p$$, $$s+t=5p$$, $$\frac{s+t}{2} = \frac{5p}{2}$$ . Sufficient.

(2) $$s+t=5p$$, $$\frac{(s+t)}{2} = \frac{5p}{2}$$. Sufficient.

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Originally posted by hazelnut on 12 Feb 2017, 19:02.
Last edited by hazelnut on 13 Feb 2017, 00:43, edited 2 times in total.
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Re: If S, P, T are there such that s<p<t, is the average (Arithmetic mean)  [#permalink]

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13 Feb 2017, 00:11
nahid78 wrote:
If S, P, T are there such that s<p<t, is the average (Arithmetic mean) of s and t equal to 5p/2?

(1) the average of s, p, and t is equal to twice of the median of them.
(2) s + t = 5p

D.

S+t/2 = 5p/2 --given ...we need to get s + t =5p

A--- s+p+t/3 =3p
=s+t = 5p --suff

B--s+t =5p --suff ...

hence D.
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Joined: 12 Mar 2013
Posts: 240
Re: If S, P, T are there such that s<p<t, is the average (Arithmetic mean)  [#permalink]

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13 Feb 2017, 00:48
Dear ziyuenlau,

you have solved it perfectly.
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We Shall Overcome... One day...

Re: If S, P, T are there such that s<p<t, is the average (Arithmetic mean) &nbs [#permalink] 13 Feb 2017, 00:48
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