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property :

for any set of consecutive set of numbers ; the +ve difference of median and mean is always '0'
option A ; 0

carcass
If set S consists of the first 10 positive even numbers, what is the positive difference between the median and the mean of set S?

(A) 0
(B) 1
(C) 2
(D) 4
(E) It cannot be determined from the information given.
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av1901
carcass
If set S consists of the first 10 positive even numbers, what is the positive difference between the median and the mean of set S?

(A) 0
(B) 1
(C) 2
(D) 4
(E) It cannot be determined from the information given.

Set S = {0, 2, 4, 6, 8, 10, 12, 14, 16, 18}

Mean = \(\frac{Sum}{10}\) = \(\frac{90}{10}\) = 9

Median = Average of \(\frac{n}{2}\)th term and \(\frac{n}{2} + 1\)th term

= Average of 5th and 6th term = \(\frac{(8+10)}{2} = 9\)

Difference between Mean & Median = 9 - 9 = 0

isnt 0 a non-negative number? so why have we considered 0 in calculation, as the ques asks specifically positive integer?
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Urvasi
av1901
carcass
If set S consists of the first 10 positive even numbers, what is the positive difference between the median and the mean of set S?

(A) 0
(B) 1
(C) 2
(D) 4
(E) It cannot be determined from the information given.

Set S = {0, 2, 4, 6, 8, 10, 12, 14, 16, 18}

Mean = \(\frac{Sum}{10}\) = \(\frac{90}{10}\) = 9

Median = Average of \(\frac{n}{2}\)th term and \(\frac{n}{2} + 1\)th term

= Average of 5th and 6th term = \(\frac{(8+10)}{2} = 9\)

Difference between Mean & Median = 9 - 9 = 0

isnt 0 a non-negative number? so why have we considered 0 in calculation, as the ques asks specifically positive integer?

You are right that 0, being a nonnegative integer, should not be part of the set. However, it's important to note that for evenly spaced sets like the consecutive even integers, the median and mean are equal. As a result, the difference between the median and mean of any evenly spaced set is always zero.
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