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Updated on: 25 Dec 2017, 22:55
Originally posted by davidfrank on 10 Dec 2012, 01:58.
Last edited by Bunuel on 25 Dec 2017, 22:55, edited 2 times in total.
Last edited by Bunuel on 25 Dec 2017, 22:55, edited 2 times in total.
Renamed the topic and edited the question.
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
71% (01:25) correct
29%
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If \(\sqrt{(x+4)^2} = 3\), which of the following could be the value of x - 4?
A. -11
B. -7
C. -4
D. -3
E. 5
A. -11
B. -7
C. -4
D. -3
E. 5
If \(\sqrt{(x+4)^2} = 3\), which of the following could be the value of x - 4?
A. -11
B. -7
C. -4
D. -3
E. 5
\(\sqrt{(x+4)^2} = 3\)
\((x+4)^2=9\)
\(x+4=3\) or \(x+4=-3\)
\(x=-1\) or \(x=-7\)
\(x-4=-5\) or \(x-4=-11\).
Answer: A.
Hope it's clear.
A. -11
B. -7
C. -4
D. -3
E. 5
\(\sqrt{(x+4)^2} = 3\)
\((x+4)^2=9\)
\(x+4=3\) or \(x+4=-3\)
\(x=-1\) or \(x=-7\)
\(x-4=-5\) or \(x-4=-11\).
Answer: A.
Hope it's clear.
10 Dec 2012, 02:33
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Bunuel
Bunuel, at 1st place why are you squaring both sides when we know that square root have a value of 1/2 which eventually cancels out the square.
\sqrt{(x+4)^2=3}
so this leaves me with x+4=3
and x=-1.
What is wrong with my approach. I know that I don't have an option of -5 in the answer but still my solution is correct.
CHeeers 
