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If the area of a circle is 64*pi, then the diameter of the circle

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If the area of a circle is 64*pi, then the diameter of the circle  [#permalink]

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New post 23 Oct 2018, 13:06
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Question Stats:

90% (00:22) correct 10% (00:56) wrong based on 44 sessions

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If the area of a circle is \(64\pi\), then the diameter of the circle is

(A) \(8\)
(B) \(16\)
(C) \(32\)
(D) \(8\pi\)
(E) \(16\pi\)

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Re: If the area of a circle is 64*pi, then the diameter of the circle  [#permalink]

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New post 23 Oct 2018, 13:33
pushpitkc wrote:
If the area of a circle is \(64\pi\), then the diameter of the circle is

(A) \(8\)
(B) \(16\)
(C) \(32\)
(D) \(8\pi\)
(E) \(16\pi\)


Area = D^2/4 * pi

64* pi = D^2/4 * pi

4 * 64 = D^2

256 = D^2

2^8 = D^2

2^4 = D

16 = D

Answer choice B

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If the area of a circle is 64*pi, then the diameter of the circle  [#permalink]

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New post 24 Oct 2018, 00:57
pushpitkc wrote:
If the area of a circle is \(64\pi\), then the diameter of the circle is

(A) \(8\)
(B) \(16\)
(C) \(32\)
(D) \(8\pi\)
(E) \(16\pi\)


Ans:
area of circle = pi*r^2 = 64*pi
r^2 = 64, r = 8,
diameter = =2r = 16

so, B is the answer
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Re: If the area of a circle is 64*pi, then the diameter of the circle  [#permalink]

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New post 24 Oct 2018, 09:02
pushpitkc wrote:
If the area of a circle is \(64\pi\), then the diameter of the circle is

(A) \(8\)
(B) \(16\)
(C) \(32\)
(D) \(8\pi\)
(E) \(16\pi\)

\(πr^2 = 64π\)

So, \(r = 8\)

Thus, Diameter of the circle must be \(2*r = 16\) ; Answer must be (B)
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Re: If the area of a circle is 64*pi, then the diameter of the circle   [#permalink] 24 Oct 2018, 09:02
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