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If the area of the trapezoid in the figure above is 27, then k =

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Joined: 02 Sep 2009
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If the area of the trapezoid in the figure above is 27, then k = [#permalink]

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05 Oct 2017, 01:27
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Difficulty:

35% (medium)

Question Stats:

71% (01:07) correct 29% (01:16) wrong based on 28 sessions

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If the area of the trapezoid in the figure above is 27, then k =

(A) 3/2√2
(B) √(3/2)
(C) 3/√5
(D) 3/2
(E) 9/4

[Reveal] Spoiler:
Attachment:

2017-10-04_1124_001.png [ 10.32 KiB | Viewed 335 times ]
[Reveal] Spoiler: OA

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Re: If the area of the trapezoid in the figure above is 27, then k = [#permalink]

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05 Oct 2017, 01:58
Area of trapezium = 1/2 x (Sum of parallel sides) x height
sides are (5k-2k)=3k and (6k-k)=5k, height is (4k-k) = 3k
Area = $$\frac{1}{2}$$ x (3k+5k) x 3k =12k^2 = 27
k^2 = $$\frac{27}{12}$$
k = $$\frac{3}{2}$$
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Re: If the area of the trapezoid in the figure above is 27, then k =   [#permalink] 05 Oct 2017, 01:58
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If the area of the trapezoid in the figure above is 27, then k =

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