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If the area of the trapezoid in the figure above is 27, then k =

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Kudos [?]: 128601 [0], given: 12180

If the area of the trapezoid in the figure above is 27, then k = [#permalink]

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New post 05 Oct 2017, 01:27
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If the area of the trapezoid in the figure above is 27, then k =

(A) 3/2√2
(B) √(3/2)
(C) 3/√5
(D) 3/2
(E) 9/4

[Reveal] Spoiler:
Attachment:
2017-10-04_1124_001.png
2017-10-04_1124_001.png [ 10.32 KiB | Viewed 142 times ]
[Reveal] Spoiler: OA

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Kudos [?]: 128601 [0], given: 12180

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Re: If the area of the trapezoid in the figure above is 27, then k = [#permalink]

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New post 05 Oct 2017, 01:58
Area of trapezium = 1/2 x (Sum of parallel sides) x height
sides are (5k-2k)=3k and (6k-k)=5k, height is (4k-k) = 3k
Area = \(\frac{1}{2}\) x (3k+5k) x 3k =12k^2 = 27
k^2 = \(\frac{27}{12}\)
k = \(\frac{3}{2}\)
Answer D.
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Kudos [?]: 62 [0], given: 236

Re: If the area of the trapezoid in the figure above is 27, then k =   [#permalink] 05 Oct 2017, 01:58
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