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# If the area of the trapezoid in the figure above is 27, then k =

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Math Expert
Joined: 02 Sep 2009
Posts: 43322

Kudos [?]: 139435 [0], given: 12790

If the area of the trapezoid in the figure above is 27, then k = [#permalink]

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05 Oct 2017, 00:27
00:00

Difficulty:

45% (medium)

Question Stats:

68% (01:03) correct 32% (01:16) wrong based on 25 sessions

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If the area of the trapezoid in the figure above is 27, then k =

(A) 3/2√2
(B) √(3/2)
(C) 3/√5
(D) 3/2
(E) 9/4

[Reveal] Spoiler:
Attachment:

2017-10-04_1124_001.png [ 10.32 KiB | Viewed 295 times ]
[Reveal] Spoiler: OA

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Kudos [?]: 139435 [0], given: 12790

Senior Manager
Status: Preparing for GMAT
Joined: 25 Nov 2015
Posts: 423

Kudos [?]: 157 [0], given: 422

Location: India
GPA: 3.64
Re: If the area of the trapezoid in the figure above is 27, then k = [#permalink]

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05 Oct 2017, 00:58
Area of trapezium = 1/2 x (Sum of parallel sides) x height
sides are (5k-2k)=3k and (6k-k)=5k, height is (4k-k) = 3k
Area = $$\frac{1}{2}$$ x (3k+5k) x 3k =12k^2 = 27
k^2 = $$\frac{27}{12}$$
k = $$\frac{3}{2}$$
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Kudos [?]: 157 [0], given: 422

Re: If the area of the trapezoid in the figure above is 27, then k =   [#permalink] 05 Oct 2017, 00:58
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