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If the area of the trapezoid in the figure above is 27, then k =

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If the area of the trapezoid in the figure above is 27, then k =  [#permalink]

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New post 05 Oct 2017, 00:27
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A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

72% (01:22) correct 28% (01:40) wrong based on 46 sessions

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If the area of the trapezoid in the figure above is 27, then k =

(A) 3/2√2
(B) √(3/2)
(C) 3/√5
(D) 3/2
(E) 9/4

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2017-10-04_1124_001.png
2017-10-04_1124_001.png [ 10.32 KiB | Viewed 563 times ]

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Re: If the area of the trapezoid in the figure above is 27, then k =  [#permalink]

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New post 05 Oct 2017, 00:58
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Area of trapezium = 1/2 x (Sum of parallel sides) x height
sides are (5k-2k)=3k and (6k-k)=5k, height is (4k-k) = 3k
Area = \(\frac{1}{2}\) x (3k+5k) x 3k =12k^2 = 27
k^2 = \(\frac{27}{12}\)
k = \(\frac{3}{2}\)
Answer D.
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Re: If the area of the trapezoid in the figure above is 27, then k =  [#permalink]

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New post 28 Nov 2018, 21:22
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Re: If the area of the trapezoid in the figure above is 27, then k = &nbs [#permalink] 28 Nov 2018, 21:22
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